Wave Power Potential: Calculating Energy Output

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Discussion Overview

The discussion revolves around calculating the energy output potential of a wave-powered generator, specifically focusing on converting the lifting of a weight by ocean waves into horsepower. Participants explore various methods and formulas for this calculation, addressing both theoretical and practical aspects of wave energy conversion.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Exploratory

Main Points Raised

  • One participant presents a scenario of lifting 10,000 lbs one foot every 2 seconds and seeks a formula for energy conversion to horsepower.
  • Another participant states that 1 horsepower equals 550 foot-pounds per second and notes the challenges of durability in wave power projects.
  • A participant suggests equating work and energy as a straightforward approach.
  • One participant calculates horsepower using the formula HP = (Force x Velocity) / 33,000, arriving at 9.09 HP based on their parameters.
  • Another participant prefers SI units and calculates power using the formula Power = mgh/t, converting the weight to kilograms and height to meters, resulting in 18 HP.
  • A participant questions the discrepancy in horsepower calculations and clarifies their preference for using horsepower due to familiarity with hydraulic systems.
  • One participant acknowledges a mistake in their height conversion, which aligns their result with another participant's calculation.

Areas of Agreement / Disagreement

Participants express differing calculations for horsepower based on their approaches, leading to a lack of consensus on the correct value. Some calculations yield 9.09 HP while others suggest 18 HP, indicating unresolved discrepancies in the discussion.

Contextual Notes

Participants rely on various assumptions, such as the consistency of wave patterns and the efficiency of energy capture, which may affect their calculations. The discussion also highlights the importance of unit conversions and the choice of measurement systems.

Who May Find This Useful

This discussion may be of interest to individuals involved in wave energy projects, hydraulic engineering, or those seeking to understand the calculations related to energy output from wave motion.

deckart
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Ocean waves are a bit random in frequency and amplitude so I'm just trying lock down a simple scenario to get an idea of the energy potential. Physics math, I know very little.

Let's say we have a steady wave pattern that lifts 10,000 lbs one foot every 2 seconds. Convert to that to an energy unit, like, horsepower. Can someone give me a formula I can work with for that?

I'm actually designing a wave powered generator but my specialty is in the hydraulic side of the project.

Thanks, and if you're interested in the project, message me.
 
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1 horsepower is 550 foot pound per second.

There are many wave power projects past and present. A common difficulty is durability. The ocean surface is a harsh environment.
 
The same as in hydraulics. Simply equate work and energy.
 
Yep, it is harsh. A block of foam is pretty resilient. The power generation is land based as opposed to having the equipment on the ocean. Just a buoy being lifted for this one.

So, 550 / 2, 10,000 lbs / 225 = 44.4 hp ?
 
With this formula I found here: http://www.iprocessmart.com/techsmart/formulas.htm
HP =
HP_2.gif

Where F = Force (lbs)
V = Velocity (ft/min)

Moving 10,000 lbs 1 ft every 2 seconds, 30 ft/min, I get:
(10,000 lbs x 30 ft/min) / 33,000 = 9.09 HP

aslo

HP = 550 lbs/ft/sec
10,000 lbs / 2 sec = 5000 lbs/sec
(5000 lbs/sec)/550 = 9.09 HP

What is cool about my device is that I'll also capture that 10,000 lb dropping at the same frequency but that side will not be as efficient. But, if I can get 50-60% of that, that will add 9.09 x .5 to the energy potential. Roughly, 15 HP. 15 HP being my target!
 
deckart said:
Let's say we have a steady wave pattern that lifts 10,000 lbs one foot every 2 seconds. Convert to that to an energy unit, like, horsepower. Can someone give me a formula I can work with for that?

Sorry I prefer to work in SI units..

Power (Watts) = mgh/t

where
m is the mass in kg = 4536 kg
g = 9.8m/s/s
h is the height in meters = 0.61m
t is the time = 2 seconds

Power = 4536 * 9.8 * 0.61/2 = 13,558W

If you want that in HP then

750w = 1HP
13558 / 750 = 18HP
 
That is twice the HP I come up with. Are we combining the energy up AND down?

I'm using HP because that is the unit I'm familiar with when working with the hydraulic side.
 
I made a mistake. 0.61m is two feet not one foot. So we get same answer.
 
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