Wave Problem (constructive interference)

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The problem involves two speakers 8.0 meters apart emitting a 76.0-Hz tone, creating points of constructive interference along the line between them. The wavelength calculated is approximately 4.513 meters. To find the distances from speaker A where constructive interference occurs, the difference in distances from both speakers must equal multiples of the wavelength (0, w, 2w, etc.). The correct approach is to set the equation for distance differences, leading to three valid solutions corresponding to 0, w, and 2w. The method highlights that solutions are limited by the distance between the speakers, confirming only three points of constructive interference exist.
tubaplaya76
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Hey everyone,

here's a problem that's been troubling me all day and I really have no idea what else to do:

"Speakers A and B are vibrating in phase. They are directly facing each other, are 8.0 m apart, and are each playing a 76.0-Hz tone. The speed of sound is 343 m/s. On the line between the speakers there are three points where constructive interference occurs. What are the distances of these three points from speaker A?"

I've found the wavelength (using v=343 and f=76) to be 4.513.

I then set up three equations, that I think in theory will give me the right answer:
(w = wavelength)
(l = length (8m))

x=w
l-x=3w

y=2w
l-y=2w

z=3w
l-z=w

However, when I submitted this each answer online, I got an incorrect answer. Any help would be appreciated. thanks in advance,

Sam
 
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tubaplaya76 said:
Hey everyone,

here's a problem that's been troubling me all day and I really have no idea what else to do:

"Speakers A and B are vibrating in phase. They are directly facing each other, are 8.0 m apart, and are each playing a 76.0-Hz tone. The speed of sound is 343 m/s. On the line between the speakers there are three points where constructive interference occurs. What are the distances of these three points from speaker A?"

I've found the wavelength (using v=343 and f=76) to be 4.513.

I then set up three equations, that I think in theory will give me the right answer:
(w = wavelength)
(l = length (8m))

x=w
l-x=3w

...

There is no reason to impose that you are at a distance w from one speaker! You could be at 1.3 w, or 0.668w or any other distance!
(btw, notice that your solution would work only if l = 4 w which is not the case here).
What you must do is to impose that the difference of distance traveled by both waves is either 0 or w or 2w and so on.

Call x the distance from the first speaker. Then l-x is the distance from the second speaker (as you already had). Then impose that the difference between the two distances is 0 or w or 2 w, etc.

so

l-x - x = 0, w, 2w , ect.

The first possibility gives you the obvious solution: right in the middle. Then you will get the others. Of course, no solution is possible when n w gets above l, which happens for the first time when n =3. so l- 2x = 3 w has no solution in your case. This shows that there are only 3 solutions (corresponding to 0, w and 2w)

Pat
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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