Wave Problem (constructive interference)

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SUMMARY

The discussion centers on a physics problem involving constructive interference from two speakers, A and B, which are 8.0 meters apart and emitting a 76.0 Hz tone. The speed of sound is given as 343 m/s, leading to a calculated wavelength of 4.513 meters. The user, Sam, initially attempted to find the points of constructive interference using incorrect equations. The correct approach involves setting the difference in distances from the speakers to be multiples of the wavelength, specifically 0, 1w, or 2w, leading to three valid solutions for the distances from speaker A.

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  • Familiarity with basic algebra and equations
  • Concept of phase difference in wave mechanics
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Hey everyone,

here's a problem that's been troubling me all day and I really have no idea what else to do:

"Speakers A and B are vibrating in phase. They are directly facing each other, are 8.0 m apart, and are each playing a 76.0-Hz tone. The speed of sound is 343 m/s. On the line between the speakers there are three points where constructive interference occurs. What are the distances of these three points from speaker A?"

I've found the wavelength (using v=343 and f=76) to be 4.513.

I then set up three equations, that I think in theory will give me the right answer:
(w = wavelength)
(l = length (8m))

x=w
l-x=3w

y=2w
l-y=2w

z=3w
l-z=w

However, when I submitted this each answer online, I got an incorrect answer. Any help would be appreciated. thanks in advance,

Sam
 
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tubaplaya76 said:
Hey everyone,

here's a problem that's been troubling me all day and I really have no idea what else to do:

"Speakers A and B are vibrating in phase. They are directly facing each other, are 8.0 m apart, and are each playing a 76.0-Hz tone. The speed of sound is 343 m/s. On the line between the speakers there are three points where constructive interference occurs. What are the distances of these three points from speaker A?"

I've found the wavelength (using v=343 and f=76) to be 4.513.

I then set up three equations, that I think in theory will give me the right answer:
(w = wavelength)
(l = length (8m))

x=w
l-x=3w

...

There is no reason to impose that you are at a distance w from one speaker! You could be at 1.3 w, or 0.668w or any other distance!
(btw, notice that your solution would work only if l = 4 w which is not the case here).
What you must do is to impose that the difference of distance traveled by both waves is either 0 or w or 2w and so on.

Call x the distance from the first speaker. Then l-x is the distance from the second speaker (as you already had). Then impose that the difference between the two distances is 0 or w or 2 w, etc.

so

l-x - x = 0, w, 2w , ect.

The first possibility gives you the obvious solution: right in the middle. Then you will get the others. Of course, no solution is possible when n w gets above l, which happens for the first time when n =3. so l- 2x = 3 w has no solution in your case. This shows that there are only 3 solutions (corresponding to 0, w and 2w)

Pat
 

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