Wave speed and distance on a guitar string

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SUMMARY

The problem involves calculating the meeting point of two wave pulses on a guitar string of length 62.9 cm, with a wave speed of 278 m/s. The string is plucked 25.1 cm from the left end, leading to the equation 25.1 cm + x = (62.9 cm - 25.1 cm) - x. The correct solution requires careful setup of the equation, resulting in x being 6.35 cm from the right end of the string. The key takeaway is the importance of accurately measuring distances from the specified reference points.

PREREQUISITES
  • Understanding of wave mechanics and pulse propagation
  • Familiarity with algebraic equations and solving for variables
  • Knowledge of guitar string physics, including length and tension effects
  • Basic principles of reflection in wave motion
NEXT STEPS
  • Study wave speed calculations in different mediums
  • Learn about wave interference and superposition principles
  • Explore the effects of string tension on wave speed
  • Investigate the physics of musical instruments and sound production
USEFUL FOR

Students studying physics, particularly those focusing on wave mechanics, as well as musicians and educators interested in the physics of string instruments.

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Homework Statement


The wave speed in a guitar string of length 62.9 cm is 278 m/s. you pluck the center of the string by pulling it up and letting go. Pulses move in both directions and are reflected off the ends of the string. If you plucked the string 25.1 cm from the left end of the string, how far from the other end of the string would the two pulses meet? In units of cm.


Homework Equations


I thought just some old-fashioned algebra could do it..


The Attempt at a Solution


What I first tried was 25.1 cm + x= Remainingcm-x, so:

25.1cm+x=(62.9-25.1)-x
25.1cm+x=37.8-x
2x=12.7
x=6.35 cm

However, this did not work.

Can anyone tell me what I'm doing wrong? Thanks.
 
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Waves meet at P a distance x from B
stringwave.png


Just be careful setting up the equation.
Measure x from the right hand side as the question asks and you can't go wrong.
 

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