Wave Velocity: Improper approach, or incorrect differentiation?

Click For Summary
SUMMARY

The discussion centers on calculating the displacement and velocity of a transverse wave represented by the equation D(x, t) = 0.19sin(2.9x - 35t). The displacement at x = 0.62 m and t = 8.6*10^-2 s is correctly found to be -0.18 m. However, the user encounters difficulties in calculating the velocity using the derivative of the wave equation. The correct approach involves applying the chain rule accurately to derive the velocity expression, which was initially miscalculated.

PREREQUISITES
  • Understanding of wave equations and their representations
  • Knowledge of differentiation, specifically partial derivatives
  • Familiarity with the chain rule in calculus
  • Ability to work with trigonometric functions in radians
NEXT STEPS
  • Review the chain rule in calculus for partial derivatives
  • Practice calculating derivatives of trigonometric functions
  • Explore wave mechanics and the properties of transverse waves
  • Learn about the relationship between wave displacement and velocity
USEFUL FOR

Students studying physics, particularly those focusing on wave mechanics, as well as educators looking for examples of wave equation applications and differentiation techniques.

rusty65
Messages
4
Reaction score
0

Homework Statement



A transverse wave on a cord is given by D(x, t) = 0.19sin(2.9x - 35t), where D and x are in m and t is in s.
1) At t = 8.6*10^-2 s, what is the displacement of the point on the cord where x = 0.62 m?
2) At t = 8.6*10^-2 s, what is the velocity of the point on the cord where x = 0.62 m?

Homework Equations



given displacement ---> D(x, t) = 0.19sin(2.9x - 35t)

The Attempt at a Solution



I didnt have any trouble finding the displacement of the wave along the cord (-0.18m) as all I had to do was plug in the given values of x and t, then make sure my calculator was in radians.

The velocity is where I ran into problems. I figured it shouldn't be any harder than taking the derivative of the given equation, then once again plugging in the supplied values. However, I did not come up with the correct answer, and I not sure if I simply differentiated incorrectly or if that is not even the correct approach. Heres my work:

0.19sin(2.9x - 35t) ---> ∂D/∂t = 0.19cos(2.9x - 35t) * (2.9 - 35t)
∂D/∂t = 0.19cos(2.9x - 35t) * (2.9 - 3.01) = (-0.11)*0.19cos(2.9x - 35t)
∂D/∂t = -0.0209cos(2.9x - 35t)
∂D/∂t = -0.0209cos(-1.212)
∂D/∂t = -0.007338 m/s

But, like I said, ∂D/∂t =/= -0.007338 m/s

Any help would be greatly appreciated.
 
Physics news on Phys.org
rusty65 said:
0.19sin(2.9x - 35t) ---> ∂D/∂t = 0.19cos(2.9x - 35t) * (2.9 - 35t)
Try this derivative again. Review the chain rule.
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
5K
  • · Replies 9 ·
Replies
9
Views
3K
Replies
23
Views
2K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
5
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K