Wavefunction Collapse: Timeline & Effects

Click For Summary

Discussion Overview

The discussion revolves around the concept of wavefunction collapse in quantum mechanics, particularly focusing on the implications of measuring a particle's energy and the subsequent state of its wavefunction over time. Participants explore the nature of wavefunction evolution, the significance of phase factors, and the behavior of photons in relation to interactions with matter and fields.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant questions whether the wavefunction remains in the collapsed state after measurement or if it reverts to its original state before further interactions occur.
  • Another participant asserts that, assuming no external interactions, the wavefunction remains in the energy eigenstate measured, evolving only by a phase factor according to Schrödinger's equation.
  • A participant expresses skepticism about the significance of the phase factor mentioned, suggesting it may not be as unimportant as stated.
  • Further clarification is provided that any state can be expressed with a phase factor, and the probability distribution remains unchanged regardless of this phase.
  • One participant revises their earlier claim about the nature of the wavefunction, indicating that it does not need to be real.
  • A question is raised regarding the behavior of photons, specifically whether they remain undisturbed in their state if they do not interact with matter, and how this relates to redshift measurements.

Areas of Agreement / Disagreement

Participants express differing views on the significance of the phase factor in wavefunctions and whether photons remain in the same state without interactions. The discussion does not reach a consensus on these points.

Contextual Notes

There are unresolved assumptions regarding the implications of wavefunction collapse and the conditions under which a particle's state may change. The discussion also touches on the effects of external fields and interactions on the state of photons, which remain open to interpretation.

Who May Find This Useful

This discussion may be of interest to those studying quantum mechanics, particularly in relation to wavefunction behavior, measurement theory, and the implications for particles like photons in various contexts.

jewbinson
Messages
127
Reaction score
0
Simple question.

So the energy of a particle is observed to be E_1 (for example) at time t=0.

At time t=0 the wavefunction psi(x) collapses to phi(x)exp(-i(E_1)t/h). At time t>0 the wavefunction is also in this state (right?). Is it in this state until it interacts with another particle or what? Or does it go into the state phi(x)exp(-i(E_1)t/h) when you observe it but then after it goes back into the state psi(x)? As far as I am aware it collapses into the state phi(x)exp(-i(E_1)t/h) for t=0 and stays in that state (but until when?) for t>0.
 
Physics news on Phys.org
Assuming no other interactions occur with the outside world, the state will state in the energy eigenstate you measured it in (up to an unimportant phase). This is because once you measure its energy, you force it into an energy eigenstate, which only change their phase when evolved with shrodingers equation
 
Thanks.

"(up to an unimportant phase)"... it's probably not unimportant is it? But I imagine it's more advanced than what I am studying now which is why you have put it to one side...
 
You can write any state as [itex]\Psi[/itex]=[itex]\psi[/itex] e, where [itex]\psi[/itex] and α are real. So when you calculate the probability distribution (the thing that is actually phzsically significant) you get [itex]\Psi[/itex]*[itex]\Psi[/itex]=[itex]\psi[/itex][itex]\psi[/itex]e-iαe=[itex]\psi[/itex][itex]\psi[/itex]. That is what I mean when I say the phase e is unimportant.
 
actually, I was wrong, [itex]\psi[/itex] does not need to be real, and in the end zou get [itex]\psi[/itex]*[itex]\psi[/itex]
 
So photons remain undisturbed (in the same state) if they don't interact with matter? Does "disturbed" include a change of a field or a change in density of an object? Would a photon ejected from a star/galaxy in red-shift relative to Earth traveling freely in space stay in the same state if it does not experience a force? If so, is this what we rely on when measuring red-shift - that the vast majority of photons from a source go through space not interacting with matter or any other field (I imagine the gravitational field has little effect on a photon actually because they have such minute mass)...?
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 16 ·
Replies
16
Views
3K
  • · Replies 0 ·
Replies
0
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 32 ·
2
Replies
32
Views
3K