Wavelength Conversion in Water: 640 nm Light & Wedge

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SUMMARY

The discussion focuses on converting the wavelength of light (640 nm) in water to its corresponding wavelengths in different media, specifically glass (n = 1.5) and water (n = 1.33). The formula used for conversion is λn = λ/n, where λ represents the wavelength in vacuum. The participants clarify that to find the wavelength in water, one must divide the original wavelength by the refractive index of water, and similarly for glass. The distance between successive bright fringes is noted as 6 mm, which is relevant for understanding interference patterns.

PREREQUISITES
  • Understanding of light wavelength and refractive index
  • Familiarity with the concept of interference patterns
  • Knowledge of basic optics equations
  • Ability to perform unit conversions in physics
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  • Research the principles of light refraction and wavelength conversion
  • Study the derivation and application of the formula λn = λ/n
  • Explore the concept of interference patterns in optics
  • Learn about the properties of different media affecting light behavior
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lha08
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Homework Statement


Light of wavelength 640 nm in water illuminates a glass (n = 1.5) wedge submerged in water (n = 1.33). If the distance between successive bright fringes is 6 mm.


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The Attempt at a Solution


I have a lot of trouble trying to convert the wavelength of light into the wavelength of water...but the rest i pretty much understand, just that little part that is really frustrating me.
 
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lha08 said:
I have a lot of trouble trying to convert the wavelength of light into the wavelength of water...but the rest i pretty much understand, just that little part that is really frustrating me.
You mean convert the wavelength of light in one medium to the wavelength it would have in another.

It's easiest if you always compare the wavelength in a medium to the wavelength in vacuum (n = 1). λn = λ/n. So, 640 nm = λ/1.33. To find the wavelength in glass, you need to figure out λ/1.5.
 

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