(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

The problem asks to find the wavelength of a tuning fork with 1000Hz frequency. Then they give you two consecutive resonant lengths which are 25 cm and 76 cm.

The way they measured the resonant lengths is by placing the tuning fork over a tube that has 1 end open and 1 end closed so that the waves come back or whatever and the lengths are the lengths of the tubes that had resonance.

2. Relevant equations

The equation i tried to use was:

Resonant length = n/4 * wavelength + end correction.

3. The attempt at a solution

So, first of all, i thought that the two consecutive harmonics were the 2nd and 3rd ones.. i cant seem to find where i justified that, so maybe thats not right, but my work assumes it is.. i guess. :p

anywho, i subtracted the 2 equations to eliminate end correction. (n's are odd because one end is open and one end is closed on the tube)

76 = 5/4 * wavelength + e

- 25 = 3/4 * wavelength + e

51 = 2/4 * wavelength

so wavelength equals 102 cm, however.. thats about 3 times as much as what it should be, which is 33-ish centimeters, and i think its because my method only works for maybe the first and 2nd harmonics or something, because it works when its just the 1st and 2nd harmonics... or i forgot to take something into consideration, i dunno, thats why im asking :D

anywho, any help would be greatly appreciated, thx.

1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Wavelength of Tuning Fork

**Physics Forums | Science Articles, Homework Help, Discussion**