Wavelength Speed Question

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Homework Help Overview

The discussion revolves around calculating the time it takes for a radio signal to travel from the ground to a satellite in geosynchronous orbit and back. The problem involves understanding the relationship between speed, distance, and time, specifically in the context of radio wave propagation.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply the formula for speed, distance, and time but expresses confusion about isolating the variable for time. Some participants explore the conversion of kilometers to meters and the need to account for the round trip of the signal.

Discussion Status

Participants are actively engaging with the problem, with some providing guidance on the mathematical steps involved. There is an exploration of the conversion process and clarification of the distance involved, but no consensus has been reached on the final calculation.

Contextual Notes

There is a mention of the original problem's parameters, including the height of the satellite and the speed of light, which are critical to the calculations being discussed. The original poster also notes a struggle with dimensional analysis and unit conversion.

jemjabella42
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Radio waves travel at the speed of light. A satellite is in a "geosynchronous orbit." A radio signal is sent from the ground to the satellite and then the satellite sends the signal back down to the ground. Satellites in geosynchronous orbit are 36,000km above the surface of the earth. How much time does it take for a signal to go from the ground to the satellite and back to the ground?

I plugged numbers into the equation speed=distance/time to get:
2.99792458x10^8 meters per second=36,000km/T

Then, I took both sides multiplied by T to get:
2.99792458x10^8 meters/sec(T)=36,000km

I am not sure how to isolate my variable from here because I'm letting the labels throw me off. I know 1km=1000meters. Do I need to use dimensional analysis to get past this step? It is very confusing for me and I don't know why! It seems like it should be simple math but my brain is just not used to it.
 
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Here we go ... like peeling layers off an onion.

v = d/t, where we use 't' for time and reserving 'T' for special intervals of time like the period of a pendulum.

then
3 x 10^8 = 2 x 36 x10^6/t thus converting km into m, noting that the signal has to return back.

Now let us 'peel off' t from the RHS

3 x 10^8 x t = 2 x 36 x10^6 .....multiplying both sides by t

then we 'peel off 3 x 10^8 from the LHS

t = 2 x 36 x10^6/3 x 10^8.....dividing both sides by 3 x 10^8

t = ...
 
grzz said:
Here we go ... like peeling layers off an onion.

v = d/t, where we use 't' for time and reserving 'T' for special intervals of time like the period of a pendulum.

then
3 x 10^8 = 2 x 36 x10^6/t thus converting km into m, noting that the signal has to return back.

Now let us 'peel off' t from the RHS

3 x 10^8 x t = 2 x 36 x10^6 .....multiplying both sides by t

then we 'peel off 3 x 10^8 from the LHS

t = 2 x 36 x10^6/3 x 10^8.....dividing both sides by 3 x 10^8

t = ...

I get confused when converting. I understand now why I need to multiply by 2 but how exactly do I arrive at 36x10^6? Could you explain this part in more detail please?
 
What do you mean by "arrive at 36x10^6"? It is given in the problem that the satellite is 36000 km above the earth. Presumably you know that there are 1000 meters in a kilometer (if you don't then it is worth memorizing "kilo= 1000") so it is 36000*(1000)= 36000000= 36*10000000= 36*10^6 meters above the earth.
 

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