Weak induction is equivalent to strong induction

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SUMMARY

The discussion centers on proving the equivalence of weak induction and strong induction in mathematical logic. The proof begins by assuming weak induction, which states that (i) 1 is in set S and (ii) if n is in S, then n+1 is also in S. The proof then shows that if these conditions hold, strong induction can be established by demonstrating that if the set {1, ..., n} is a subset of S, then n+1 must also be in S, ultimately concluding that S equals the set of natural numbers, ℕ.

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  • Understanding of mathematical induction principles
  • Familiarity with set notation and definitions
  • Basic knowledge of natural numbers and their properties
  • Ability to construct logical proofs in mathematics
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  • Study the differences between weak induction and strong induction in detail
  • Explore examples of proofs using strong induction
  • Learn about the implications of induction in number theory
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Mathematics students, educators, and anyone interested in formal proofs and the foundations of mathematical logic will benefit from this discussion.

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Homework Statement



Prove that weak induction is equivalent to strong induction.

Homework Equations



To prove this...we assume weak induction. That is

(i) 1 \in S
(ii) n\in S \Rightarrow n+1 \in S for all n in N


The Attempt at a Solution



So to prove strong induction we need to prove the following:
(i) 1 \in S
This is given by our assumption of weak induction.
(ii) {1...n} \in is a subset of S.
SInce we know 1 is in S, we can make 2...n by 1+1, 1+1+1, 1+...+1 (n times)
(iii) if (ii) is true than n+1 is in S.
I think this is true because our assumption guaranteed this.

This is a rough sketch of what I wan to say. Am I on the right track.
 
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So assume weak induction, that is:

If
(i) 1\in S
(ii) n\in S~\Rightarrow~n+1\in S
then S=\mathbb{N}.

You need to prove that strong induction holds. That is, you assume that
(a) 1\in S
(b) \{1,...,n\}\in S~\Rightarrow~n+1\in S.
You need to prove from (a) and (b) that S=\mathbb{N}. You don't need to prove (a) and (b), they are given.
 

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