Weight of 2 Blocks on an Incline

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SUMMARY

The discussion centers on the physics problem involving two blocks on an incline, specifically Block A sliding down while Block B is restrained. Both blocks have equal weight, denoted as w, and the incline angle is 45 degrees. The key point of contention is the correct representation of forces acting on Block A, particularly the normal forces and the weight. The professor's solution suggests a combined weight of w+w acting on Block A, which is debated by the participants, who argue that Block A should only experience the normal force from Block B and its own weight w.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with free body diagrams
  • Knowledge of frictional forces and coefficients
  • Basic principles of inclined planes in physics
NEXT STEPS
  • Study the concept of normal forces in multi-body systems
  • Learn about friction coefficients and their implications in physics problems
  • Review free body diagram techniques for complex systems
  • Explore inclined plane dynamics and the effects of angles on force distribution
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding the dynamics of forces on inclined planes and the interaction between multiple bodies. It is particularly relevant for those studying mechanics and preparing for exams involving similar problems.

Sean Smith
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Homework Statement


Block B rests on Block A. Block B is restrained with a string, while Block A slides down the incline. During the time Block A is between Block B and the inclined plane, Block A slides with constant velocity. If the weight of Blocks A and B are both w, and the coefficient of friction is the same between Block A and B and between Block A and the plane, find the value of the coefficient of friction u. [The angle of the incline is 45].

Homework Equations


The professor's solution has a free body diagram for Block A, with two frictional forces and a normal force. This I understand, but he draws weight straight down with magnitude w+w. I thought this was incorrect, as Block A only experiences a Normal force from Block B.

The Attempt at a Solution


The rest of the problem is inconsequential, but my proposed diagram for Block A has 2 frictional forces up the slope, Normal A normal to the slope, Normal B perpendicular to the surface between Blocks A and B, and weight of w.
 

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Sean Smith said:
This I understand, but he draws weight straight down with magnitude w+w. I thought this was incorrect, as Block A only experiences a Normal force from Block B.

If block B wasn't there, wouldn't you still draw a force of w acting on block A ?
 
Stephen Tashi said:
If block B wasn't there, wouldn't you still draw a force of w acting on block A ?
My bad wording, I thought that Block A would have Weight w and Normal force from B. I drew this in the picture I attached to the original post if you'd like to take a look. (:
 
I can't tell anything from that picture.
 
The attached picture looks fine, but I presume this is your picture, not your professor's. Without an exact reproduction of what your professor said/drew it will be impossible to tell whether you simply misunderstood. Do you arrive at different answers?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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