Weight of copper hanging/submerged

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The discussion centers on the buoyancy of a copper object submerged in fresh water. A scale initially reads 220N when the copper is hanging, and the volume of the copper is calculated to be 0.0025m³. The buoyant force acting on the copper can be determined using the formula for buoyancy, which states that the buoyant force equals the weight of the displaced fluid. Given the density of fresh water at 1000 kg/m³, the scale will read 220N minus the buoyant force when the copper is submerged.

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A scale reads 220N when a piece of copper is hanging from it. What does the scale read when it is lowered so the copper is submerged in fresh water.

From a given chart

Density:
copper is 8930 kg/m^3
fresh water is 1000kg/m^3

I found my volume of copper to be .0025m^3

I'm just not sure which direction to go now?
 
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What forces are involved in buoyancy? Draw a free body diagram. Also write down the definition of buoyancy? Does anything click?
 
Since when was volume measured in Kg?
 
The forces involved are those from bottom and those on top of object. I have drawn the diagram and I think I know the connection I'm trying to make. The volume of the displaced fluid times density has to relate to the buoyant force? I think its the Newtons that's throwing me off
 
Integral said:
Since when was volume measured in Kg?

indeed my teach would've smacked me
 
geezzzz nevermind I got it. I thought i was looking over something simple.While obtaining the forces I was neglecting my 9.8m/s^2
 

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