Insulated Copper Block Heated to 60 Celsius

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SUMMARY

The discussion focuses on calculating the time required for an insulated copper block to reach 60°C from an initial temperature of 20°C, given a power input of 100 W from an embedded resistor. The specific heat of copper is 0.385 kJ/kg·K, and the density is 8930 kg/m³. The mass of the copper block is calculated to be 8.930 kg. Using the formula Q = mcΔT, the energy required to raise the temperature is determined, leading to the conclusion that the time taken can be calculated by dividing the total energy by the power input.

PREREQUISITES
  • Understanding of specific heat capacity and its application in thermal calculations
  • Knowledge of density and mass calculations for solids
  • Familiarity with the relationship between power, energy, and time
  • Basic proficiency in algebra for manipulating equations
NEXT STEPS
  • Calculate the total energy required using Q = mcΔT for the copper block
  • Determine the time taken to reach the desired temperature using the formula time = energy/power
  • Explore the implications of insulation on heat transfer in solid materials
  • Investigate the effects of varying power inputs on heating times for different materials
USEFUL FOR

Students in physics or engineering, educators teaching thermodynamics, and anyone interested in thermal energy transfer and heat capacity calculations.

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Homework Statement


An insulated copper block receives energy at a rate of 100 W from an embedded resistor. If the block has a volume of 10-3m3 and an initial temperature of 20°C, how long would it take, in minutes, for the temperature to reach 60°C?


Homework Equations



Copper specific heat = 0.385 KJ/Kg°K

Copper Density = 8930 Kh/m3

Q' = du/dt + d(KE)/dt + d(PE)/dt + W but there is no kinetic energy, potential energy or work done

Q = mcΔT


The Attempt at a Solution



Initially, I found the mass of the copper

mcopper = (8930 Kg/m-3)(10-3m3)
mcopper = 8.930 Kg

But I'm not sure if this will help me.

How do I interpret the energy give? Is the 100 W = Q?
 
Physics news on Phys.org
A watt is a unit of power, and the common name for the unit grouping: Joules/second.

Multiply watts by time to obtain the energy delivered over that time.
 

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