Weight on a Scale Down an Incline vs. True Weight

Click For Summary
SUMMARY

The discussion focuses on the physics problem involving Judy, who uses bathroom spring scales on a skateboard descending a 30-degree incline. The calculations reveal that the scales indicate a weight that is three-quarters of Judy's true weight, derived from the equations Fg = mg and Fg_|_ = mgsin60º. The necessity of friction is highlighted, as it prevents Judy from slipping off the scales while they accelerate down the slope together.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with trigonometric functions in physics
  • Knowledge of forces acting on objects on inclined planes
  • Basic algebra for solving equations
NEXT STEPS
  • Study the concept of forces on inclined planes in physics
  • Learn about the role of friction in motion and stability
  • Explore the derivation of weight components using trigonometry
  • Investigate the effects of acceleration on objects in non-inertial frames
USEFUL FOR

Students studying physics, educators teaching mechanics, and anyone interested in understanding forces on inclined surfaces.

Error
Messages
6
Reaction score
0
Weight on a Scale Down an Incline vs. True Weight

Homework Statement


Judy fastened a set of bathroom spring scales to a wedge shaped skate board as shown and coasted freely down a 30 degree slope. The wheels were well oiled and the platform supporting the scales was horizontal. What fraction of her true weight was indicated by the scales?
Why would there need to be a force of friction between Judy and the scales?


Homework Equations


Fg = mg


The Attempt at a Solution


(Pictures in attachments)

Fg = mg
Fg_|_ = mgsin60º

FN = Fg _|_
FN = mgsin60º

FNy = FNcos30º
FNy = mgsin60ºcos30º
FNy = (3/4)mg

The weight will be 3/4 the true weight. (I think)


I'm not too sure why there will have to be friction between Judy and the scale. Will the scale accelerate downwards and she will slip off if there's no friction? Will the scale read zero?
 

Attachments

  • original.PNG
    original.PNG
    1.3 KB · Views: 731
  • forces.PNG
    forces.PNG
    2.9 KB · Views: 790
Physics news on Phys.org
Your reasoning (and perhaps your trig) is a bit unclear. Try this: What's the acceleration of the woman?
 

Similar threads

  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
6
Views
3K
Replies
1
Views
3K
  • · Replies 10 ·
Replies
10
Views
10K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 24 ·
Replies
24
Views
4K
  • · Replies 10 ·
Replies
10
Views
4K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 2 ·
Replies
2
Views
3K