Well-lubricated bicycle wheel problem

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SUMMARY

The discussion centers on calculating the number of revolutions a well-lubricated bicycle wheel makes while stopping from an initial speed of 170 rpm over a duration of 70 seconds. The user converted the initial speed to 17.80 rad/s and attempted to apply the circular motion kinematics equations to find the angular acceleration and total revolutions. The correct approach involves using the equation for angular displacement, which incorporates initial angular velocity, angular acceleration, and time. The user also highlights the importance of distinguishing between rpm and revolutions per second for accurate calculations.

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Homework Statement


A well-lubricated bicycle wheel spins a long time before stopping. Suppose a wheel initially rotating at 170 rpm takes 70 s to stop.

A)If the angular acceleration is constant, how many revolutions does the wheel make while stopping?


Homework Equations


i used circular motion kinematics equations.


The Attempt at a Solution


i changed 170 rpm to 17.80 rad/s. then i used wf=wi+(alpha)(delta)t
wf=17.80 rad/s + (0-70s) = -52.2 rad/s^2
i used (theta)F= (theta)i + wi (delta)t +1/2 ((alpha)(delta)t)^2

i think i used the right equations but when i solve for wf i get -581 rad... don't know if that's the right answer.

i'd greatly appreciate the help :)
 
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I think you are making this unnecessarily complex.

If the wheel starts at 170rpm at T=0 and is at 0rpm at T=70 and we know the deceleration is constant, what rotational speed was it turning at at T=35?
If we know that what can we do with that information?

Beware of rpm and revs per second!
 

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