1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

What am I doing wrong in this derivative

  1. Mar 11, 2014 #1
    my derivative of log4(r)*log2(r)= log2(r)/rln(4)+log4(r)/rln(2)

    my book says the derivative should be 2(ln(r))/(r(ln(2))(ln(4))
    what am I doing wrong?
     
  2. jcsd
  3. Mar 11, 2014 #2
    Do you know how to convert logs to different bases?
     
  4. Mar 11, 2014 #3

    Ray Vickson

    User Avatar
    Science Advisor
    Homework Helper

    What does log4(r) mean? Is it ##\log(4r)##, log to base 4 of r, or is it ##\log(r)^4##?
     
  5. Mar 11, 2014 #4

    pasmith

    User Avatar
    Homework Helper

    You can simplify your expression further:
    [tex]
    \frac{\log_2(r)}{r \ln 4} + \frac{\log_4(r)}{r \ln 2} =
    \frac{\ln r}{(r \ln 4) \ln 2} + \frac{\ln r}{(r \ln 2) \ln 4}
    = \frac{2 \ln r}{r \ln 2 \ln 4}
    [/tex]
     
  6. Mar 11, 2014 #5
    1/ln(b)*1/r* dy/dx(r)
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: What am I doing wrong in this derivative
  1. What am I doing wrong? (Replies: 5)

  2. What am i doing wrong? (Replies: 2)

Loading...