A uniform stick 1.0 m long with a total mass of 220 g is pivoted at its center. A 3.2 g bullet is shot through the stick midway between the pivot and one end The bullet approaches at 250 m/s and leaves at 140 m/s
With what angular speed is the stick spinning after the collision?
I of stick = (1/12)ML^2
The Attempt at a Solution
(1/2)*Mb*Vi^2 = (1/2)(Mb*Vf^2+(1/2)Iw^2
i use the above equaltion but it wrong
anyone got any idea how to solve this XD
please help me ^_^