What are are the magnitude and direction

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SUMMARY

The electric field vector is given as E = (215, -380) V/m. To determine the magnitude, apply the Pythagorean theorem, resulting in a magnitude of approximately 445.25 V/m. The direction can be calculated using the arctangent function, yielding an angle of approximately 303.6 degrees from the positive x-axis.

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  • Knowledge of trigonometric functions, specifically tangent and arctangent
  • Ability to apply the Pythagorean theorem
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  • Learn about electric field calculations in different coordinate systems
  • Explore the use of trigonometric functions in physics problems
  • Investigate applications of electric fields in scientific instruments
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gbedenba
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Homework Statement


The quantity called the electric field is a vector. The electric field inside a scientific instrument is = (215 - 380 ) V/m, where V/m stands for volts per meter. What are the magnitude and direction of the electric field?

_____ v/m

______ degree (smallest positive angle from the positive x-axis)

Homework Equations



?

The Attempt at a Solution



I don't know where to start
 
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Welcome to PF!

Hi gbedenba! Welcome to PF! :smile:
gbedenba said:
The quantity called the electric field is a vector. The electric field inside a scientific instrument is = (215 - 380 ) V/m, where V/m stands for volts per meter. What are the magnitude and direction of the electric field?

Do you mean that the x and y coordinates are 215 and -380? :confused:

Use Pythagoras, and tangent. :wink:
 

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