What Are Implicit Functions and Ordered Pairs in Algebra?

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Homework Statement


:mad::mad::mad:Find two functions defined implicitly by the relation 9y^2=x^2
[tex]9y^{2}=x^{2}[/tex]


2. Find three ordered pairs in the relation xy=12



The Attempt at a Solution



1. my attempt is [tex]f(x)= \sqrt{9y^{2}}[/tex]

and

[tex]f(y)=\sqrt{\frac{x^{2}}{9}}[/tex]
So...is this the right way to do this question?
am i allowed to put a f() around my x and y and then solve for x and y?


2. I guess it would be either (2,6) OR (3,4) OR (1,12)
Is this correct and what the heck is an ordered pair?
 
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I think you are on the right track. The two relations would be f(x) and f(y), I think. And solving for the ordered pairs (x,y) would be along the lines you suggest.
 
If 9y^2=x^2 and you solve for y, what do you get?

y = [tex]\pm\frac{x}{3}[/tex]

The y is the result of the function... ie f(x), g(x) etc...

So the two functions implicit here are:

f(x) = x/3 and g(x) = -x/3
 
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