What Are Implicit Functions and Ordered Pairs in Algebra?

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Homework Help Overview

The discussion revolves around understanding implicit functions and ordered pairs in algebra, specifically through the relation 9y² = x² and the equation xy = 12.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to define functions based on the implicit relation and seeks clarification on the validity of their approach. They also question the concept of ordered pairs and provide examples they believe may fit the relation xy = 12.

Discussion Status

Some participants affirm the original poster's approach and suggest that the relations can be expressed as functions. Others contribute by solving for y in the implicit equation and identifying the resulting functions.

Contextual Notes

The original poster expresses confusion regarding the definition of ordered pairs and the process of defining functions from implicit relations.

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Homework Statement


:mad::mad::mad:Find two functions defined implicitly by the relation 9y^2=x^2
9y^{2}=x^{2}


2. Find three ordered pairs in the relation xy=12



The Attempt at a Solution



1. my attempt is f(x)= \sqrt{9y^{2}}

and

f(y)=\sqrt{\frac{x^{2}}{9}}
So...is this the right way to do this question?
am i allowed to put a f() around my x and y and then solve for x and y?


2. I guess it would be either (2,6) OR (3,4) OR (1,12)
Is this correct and what the heck is an ordered pair?
 
Last edited by a moderator:
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I think you are on the right track. The two relations would be f(x) and f(y), I think. And solving for the ordered pairs (x,y) would be along the lines you suggest.
 
Thanks you!.
 
If 9y^2=x^2 and you solve for y, what do you get?

y = \pm\frac{x}{3}

The y is the result of the function... ie f(x), g(x) etc...

So the two functions implicit here are:

f(x) = x/3 and g(x) = -x/3
 
Last edited:

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