What Are the Characteristics of Protonium?

[stunner5000pt]

Protonium consists of Proton and an antiproton in a bound state

first of all what is a bound state - is it a proton orbiting an antiproton or vice versa??

a) what is the Binding energy of protonium?
do i use this formula??

E = \frac{ \mu e^4}{8 \epsilon_{0}^2 h^2}

b) How far apart are the antiproton and proton in this ground state??

r = \frac{\epsilon_{0} h^2}{\mu \pi Z e^2} n^2

where \mu = \frac{m_{p}^2}{2m_{p}} = \frac{m_{p}}{2}

c) What is the angular momentum of the proton or antiproton in the 3rd excited state?

so the 3rd excited state is n = 4

L = \mu v r = n \frac{h}{2 \pi}

and i find v using the formula given??

andi right so far if you could correct me on any of these please please tell me!

also i coul also use your help for this thread too, similar topic question!

https://www.physicsforums.com/showthread.php?t=52658

 

[wais]

a) The binding energy of protonium can be calculated using the formula you provided. However, it is important to note that this formula is for the binding energy of a single electron to a nucleus, so it may not accurately represent the binding energy of a proton-antiproton pair. A more accurate calculation would involve solving the Schrödinger equation for the protonium system.

b) The formula you provided for the distance between the antiproton and proton in the ground state is correct. However, the value of \mu you have used is incorrect. It should be \mu = \frac{m_{p}m_{\bar{p}}}{m_{p}+m_{\bar{p}}} where m_{p} and m_{\bar{p}} are the masses of the proton and antiproton, respectively.

c) To find the angular momentum in the 3rd excited state, you can use the formula L = \mu v r = n \frac{h}{2 \pi}. However, you will need to use the correct value of \mu as mentioned above, and also substitute the value of n = 4.

I am not able to access the thread you mentioned, so I am unable to provide any help for it. However, I suggest seeking guidance from your instructor or a physics tutor for any further assistance with this topic.