The Ground State Orbit of a W+73 Atom: Is It Bohr-rific?

AI Thread Summary
The discussion focuses on the W+73 atom, derived from tungsten, and explores the energy required to remove the last electron using the Bohr model. The energy of the electron is calculated with the formula E = -Z^2 (me^4)/(8 ε0^2 h^2 n), which is also the energy needed to strip the electron from orbit. Participants agree that the non-relativistic assumption of the Bohr model is valid for this atom, as it resembles a highly charged hydrogen atom. The orbital speed of the electron is derived from v = Ze^2/(2 ε0 h) and further calculations are suggested to determine the wavelength and radius of the orbit. Overall, the Bohr model appears applicable to the ground state of the W+73 atom.
stunner5000pt
Messages
1,443
Reaction score
4
The nucleus of Tungsten conssits of 74protons and 110 neutrons. SUppose all of the electrons were stripped off, but one, leaving a W+73 atom.
Using the Bohr idea of the atom (not anything else!)
How much energy nrequired to remove this last electron from orbit??

The energy of the elctron in this state is

E = -Z^2 \frac{m e^4}{8 \epsilon_{0}^2 h^2 n}

and the energy to strip this electron from orbit is equal to this energy (yes??)

b) is the ususal assumption for the Bohr atom being nonrelaiivistic good for this atom?

i woul think yes because this atom only consists of two bodies and is very much like a much higher charged hydrogen atom

c)What is the wavelength of hte ecetron is this orbit?

first i must find the orbital speed but v = \frac{Ze^2}{2 \epsilon_{0} h} \frac{1}{n}

and then use \lambda = \frac{h}{m_{e} v}

d)Radius of the tungsten atom is 10^-13m Does the idea of a Bohr atom apply for the ground state of the W+73 atom?

I owuld think yes because a bohr atom is a pointcharge oribiting a heavy nucleus.
 
Last edited:
Physics news on Phys.org
i have a correction for the B part

since the radius is given to be 10^-13 metres

v = \sqrt{\frac{Ze^2}{4 \pi \epsilon_{0} r} and thereafter the velocity can be found
 
Some comments and hints.
stunner5000pt said:
How much energy nrequired to remove this last electron from orbit??

The energy of the elctron in this state is

E = -Z^2 \frac{m e^4}{8 \epsilon_{0}^2 h^2 n}

and the energy to strip this electron from orbit is equal to this energy (yes??)
Looks good. That's the total energy of the n-th level.
b) is the ususal assumption for the Bohr atom being nonrelaiivistic good for this atom?

i woul think yes because this atom only consists of two bodies and is very much like a much higher charged hydrogen atom
What's the speed of the electron in the ground state? How does it compare to c?

While you're at it, figure out the speed and radius of the ground state orbit, according to the Bohr model.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top