What Are the Correct Euler's Angles for Rotating a Cube?

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Homework Statement


What are the Euler's angles corresponding to the rotations of a cube in [tex]\theta[/tex] radians around each of its principal axes



around the x: [tex]\theta[/tex]=[tex]\theta[/tex]
[tex]\phi[/tex]=[tex]\psi[/tex]=0

around z:[tex]\psi[/tex]=[tex]\theta[/tex]=0
[tex]\phi[/tex]=[tex]\theta[/tex]

around y:[tex]\phi[/tex]=[tex]\theta[/tex]=[tex]\theta[/tex]
[tex]\psi[/tex]=-[tex]\theta[/tex]


is it correct? how can I make it more clear? It's very confusing...
 
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In order to formalize the solution you can use the rotation matrices: [tex]\hat{R}_x(\alpha)[/tex], [tex]\hat{R}_y(\alpha)[/tex], [tex]\hat{R}_z(\alpha)[/tex] and the matrix which describes the whole Euler's transform:

[tex] \hat{R}(\theta, \phi, \psi) =<br /> \hat{R}_z(\phi) \hat{R}_x(\theta) \hat{R}_z(\psi) \quad (1)[/tex]

It's easy to get rotation around the x and z axes from (1) and your answers for these cases are right.

As for y-axis the condition

[tex] \hat{R}(\theta, \phi, \psi) = \hat{R}_y(\alpha)[/tex]

yields

[tex] \theta = -\frac{\pi}{2} - \alpha;[/tex]

[tex] \phi = \psi = -\frac{\pi}{2}.[/tex]