The discussion focuses on constructing a deterministic finite automaton (DFA) for the language L defined over the alphabet {a, b}, where the condition is that the number of occurrences of the symbol 'a' in any string w must satisfy the condition n_a(w) mod 3 < 1. The solution involves creating three states {0, 1, 2} that represent the remainders when the count of 'a's is divided by 3. The automaton transitions to the next state upon reading an 'a' while remaining in the same state when reading a 'b'. The key point is that the accepting state corresponds to the condition mod 3 = 0, which indicates that the number of 'a's is a multiple of 3. The original poster successfully determined the accepting states after interpreting the condition correctly.