What are the Eigenvectors of the Integration Operator with Cosine Kernel?

Click For Summary
SUMMARY

The discussion focuses on finding the eigenvalues and eigenvectors of the integration operator defined by Af(x) = ∫₀¹ cos(2π(x - y)) f(y) dy. The kernel K(x, y) = cos(2π(x - y)) is central to this problem. Participants suggest differentiating the operator with respect to x twice to transform the integral equation into a differential equation, facilitating the identification of eigenfunctions and corresponding eigenvalues.

PREREQUISITES
  • Understanding of integral operators and their properties
  • Knowledge of eigenvalues and eigenvectors in functional analysis
  • Familiarity with differential equations and their solutions
  • Basic concepts of Fourier series and orthogonality
NEXT STEPS
  • Study the properties of integral operators in functional analysis
  • Learn about eigenvalue problems related to differential equations
  • Explore the application of Fourier series in solving integral equations
  • Investigate the relationship between kernels and their corresponding eigenfunctions
USEFUL FOR

Mathematicians, physicists, and students studying functional analysis, particularly those interested in eigenvalue problems and integral equations.

220205
Messages
3
Reaction score
0

Homework Statement



Find the eigenvalues and a corresponding system of eigenvectors of the operator

Af(x) := Integration from 0 to 1 K(x; y)f(y) dy
where
K(x; y) = cos (2pi(x - y))
 
Physics news on Phys.org
so you want
[tex]Af(x) = \int_0^1 dy \ cos (2 \pi(x - y)) f(y) = \lambda f(x)[/tex]
what ideas do you have for finding the functions
 
I'm thinking differentiate w.r.t x twice, this should turn it into a differential equation.
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
9
Views
2K
Replies
8
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
4
Views
3K
Replies
3
Views
2K
Replies
1
Views
2K
Replies
17
Views
2K
Replies
5
Views
2K