What are the forces acting on a child pulling a wagon up an inclined hill?

Click For Summary
SUMMARY

A child pulls a wagon with a mass of 7.38 kg up a hill inclined at 14.3 degrees, applying a force parallel to the incline. The calculated force applied by the child is 18.3 N, while the normal force acting on the wagon is 70.1 N. The net force equation utilized is Fnet = ma, with the gravitational components calculated using the cosine function. The solution emphasizes the importance of ensuring the calculator is set to degree mode for accurate results.

PREREQUISITES
  • Understanding of Newton's second law (Fnet = ma)
  • Knowledge of gravitational force components (Fgx and Fgy)
  • Familiarity with trigonometric functions, specifically cosine
  • Ability to perform calculations in degree mode on a scientific calculator
NEXT STEPS
  • Study the application of Newton's laws in inclined plane problems
  • Learn about the role of friction in force calculations
  • Explore advanced topics in dynamics, such as non-negligible friction
  • Investigate the effects of varying mass and incline angles on force calculations
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and dynamics, as well as educators seeking to explain forces on inclined planes.

IbrahimA
Messages
11
Reaction score
0

Homework Statement


A child is pulling a wagon of mass 7.38 kg up a hill inclined at an angle of 14.3 degrees to the horizontal. The child applies a force parallel to the hill. The acceleration of the wagon is 6.45 cm/s^2 up the hill. Friction is negligible. Determine the magnitude of (a) the force applied by the child, and (b) the normal force on the wagon.

FBD Diagram I drew:
hShKWw8.jpg


Correct Answers on book:
(a) 18.3 N
(b) 70.1 N

Homework Equations


Fnet = ma

(a) Fnet = -Fgx + Fa
(b) Fn = -Fgy

The Attempt at a Solution


(a)
Fnet = (-Fgx) + Fa
ma = m(-g)(cos14.3) + Fa
(7.38)(0.0645) = (7.38)(-9.8)(cos14.3) + Fa
71.9 N = Fa

(b)
Fn = Fgy
Fn = (7.38)(-9.8)(cos14.3)
Fn = 11.7 N


 
Physics news on Phys.org
Welcome to PF!

Note that you've used the cosine function for getting both Fgx and Fgy.

Make sure your calculator is in "degree mode".
 
TSny said:
Welcome to PF!

Note that you've used the cosine function for getting both Fgx and Fgy.

Make sure your calculator is in "degree mode".

I literally just checked it now, its was on radians. I redid the calculations and they are correct.
Thank you so much.
 
Good work!
 

Similar threads

Replies
9
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 9 ·
Replies
9
Views
5K
  • · Replies 9 ·
Replies
9
Views
14K
Replies
3
Views
4K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
2
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
6
Views
2K
Replies
2
Views
4K