What are the forces acting on the 2 kg mass?

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SUMMARY

The discussion focuses on calculating the forces acting on a system of blocks with a total mass of 6 kg, subjected to a 40-N force on a frictionless surface. The acceleration of the system is determined to be 6.67 m/s² using Newton's second law (F=ma). The tension in the cord connecting the 3.0-kg and 1.0-kg blocks is calculated to be either 99 N or 66 N, depending on the mass considered, while the force exerted by the 1.0-kg block on the 2.0-kg block is found to be 20.1 N.

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Homework Statement


Assume the three blocks portrayed in the figure below move on a frictionless surface and a force F = 40-N acts as shown on the m = 3.0-kg block.
p4_27alt.gif

(a) Determine the acceleration given this system.
(b) Determine the tension in the cord connecting the 3.0-kg and the 1.0-kg blocks.
(c) Determine the force exerted by the 1.0-kg block on the 2.0-kg block.


Homework Equations


F=ma


The Attempt at a Solution


a. F=ma
40N = (1kg + 2 kg + 3kg)a
a=6.67 m/s2

b. T=m(a+g)
T= 6kg (6.67 m/s2 + 9.8 m/s2)
T=99N
OR (I tried both)
T=4kg (6.67 m/s2 + 9.8 m/s2)
T=66N

c. F=ma
F= 3kg(6.7 m/s2)
F=20.1 N
foc
 
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mandy9008 said:

The Attempt at a Solution


a. F=ma
40N = (1kg + 2 kg + 3kg)a
a=6.67 m/s2
Good.

b. T=m(a+g)
T= 6kg (6.67 m/s2 + 9.8 m/s2)
T=99N
OR (I tried both)
T=4kg (6.67 m/s2 + 9.8 m/s2)
T=66N
Not sure where you are getting g from in your equations. The only forces we care about here are horizontal.

Hint: Analyze the forces acting on the 3 kg mass.

c. F=ma
F= 3kg(6.7 m/s2)
F=20.1 N
Why 3 kg? Hint: Analyze the forces acting on the 2 kg mass.
 

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