- #1

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is ln(E(x^n)) equal to E(ln(x^n)), if x is a continuous variable and x>=0???

Help me! Thanks!!!!!!!

Help me! Thanks!!!!!!!

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- Thread starter xuej1112
- Start date

- #1

- 18

- 0

is ln(E(x^n)) equal to E(ln(x^n)), if x is a continuous variable and x>=0???

Help me! Thanks!!!!!!!

Help me! Thanks!!!!!!!

- #2

Gib Z

Homework Helper

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This would more appropriately have been placed in the Calculus and Beyond homework help section, even if it isn't homework it is of that nature and level. General Math is more suited for general discussion of mathematical ideas.

Anyway, what is E? Is it the exponential function? How are the exponential function and natural logarithm related.

- #3

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Sorry. E is the expectation

- #4

Gib Z

Homework Helper

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Oh ok. In that case, no it's not true. In fact, in general E(g(x)) is not equal to g(E(x)) which is due to the definition of E(x) as an integral with x as the integrand. This makes it inherently difficult for these nice properties to occur, as integrals don't have "nice" properties past linearity. So while E(aX+bY) = aE(X) + bE(Y), E(X^n) is not anything nice in terms of E(x).

- #5

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thanks. if g is a concave function, can i say g(E(x))>=E(g(x)) ? (jensen's inequality)

- #6

Gib Z

Homework Helper

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It's the other way around, g(E(X)) is LESS or equal to E(g(X)), if g is convex (not concave).

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