What are the Kinematics of a Car Plunging off the Grand Canyon Edge?

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Homework Help Overview

The discussion revolves around a kinematics problem involving a car falling off the edge of the Grand Canyon, with a specific focus on calculating the time to impact and the vertical impact velocity. The scenario assumes a drop of 500 meters and involves free fall dynamics.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the use of kinematic equations to find the time of fall and final velocity, questioning the initial conditions and whether the initial vertical velocity should be considered. There is also discussion about the nature of the equations and the implications of the values used.

Discussion Status

The conversation is ongoing, with participants providing guidance on how to approach the problem using the given equations. Some participants are questioning assumptions about initial velocity and the applicability of quadratic solutions, indicating a mix of interpretations and attempts to clarify the setup.

Contextual Notes

There is a focus on the assumption of free fall and the initial conditions of the problem, particularly regarding the vertical and horizontal components of motion. The discussion reflects uncertainty about the correct application of the kinematic equations in this context.

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Homework Statement



Thelma and Louise's car falls off the edge of the Grand Canyon and plunges to certain catastrophe below. The depth of the canyon at this point is 500 m. (Assume it drops off)

A) How long will it take the vehicle to impact the canyone bottom?

B) What will the vertical impact velocity be? Do you think they will survive, even with air bags?

Homework Equations



d = vit + 1/2at^2

d = (vi+vf)t
2

The Attempt at a Solution



d - 500m
ag = -9.81 m/s^2
vi = 0m/s
t =?

Since you can't solve for t, i solved for Vf.

Would the Vf be a negative number?

Then, i pluged the vi and vf into the 2nd equatioon above, but the answer i got was different from the answer given.
 
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Why can't you solve for t?
 
o wait, maybe i made a mistake.
 
I forgot that my Vi = 0 m/s therefore does not equate to a quadratic.
 
Well, use the first equation you wrote to solve for t. You know all the information you need to solve for part a.

The D = -500 m a = -g t=? and vi= 0 The reason why I say there is no initial velocity is because once the car goes over the edge and starts to fall, it's in free fall. The car may have HORIZONTAL velocity, but there is no initial vertical velocity.

Use that information and you can solve for v final.
 
Even if it's quadratic, why wouldn't you be able to solve for t?
 

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