What are the Kinematics of a Car Plunging off the Grand Canyon Edge?

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SUMMARY

The discussion focuses on calculating the kinematics of a car falling off the Grand Canyon, specifically addressing the time to impact and the vertical impact velocity. The depth of the canyon is established at 500 meters, with gravitational acceleration set at -9.81 m/s². The initial vertical velocity (vi) is zero, leading to the use of the equation d = vit + 1/2at² to determine the time of fall and final velocity. The participants clarify that the car's initial vertical velocity is zero upon falling, emphasizing the importance of correctly applying kinematic equations to solve for time and final velocity.

PREREQUISITES
  • Understanding of basic kinematic equations, specifically d = vit + 1/2at²
  • Knowledge of gravitational acceleration, specifically -9.81 m/s²
  • Familiarity with concepts of free fall and initial velocity
  • Ability to solve quadratic equations in physics contexts
NEXT STEPS
  • Study the application of kinematic equations in free fall scenarios
  • Learn about the effects of air resistance on falling objects
  • Explore the concept of horizontal vs. vertical motion in physics
  • Investigate the implications of impact velocity on vehicle safety
USEFUL FOR

Students studying physics, educators teaching kinematics, and anyone interested in the dynamics of free-falling objects.

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Homework Statement



Thelma and Louise's car falls off the edge of the Grand Canyon and plunges to certain catastrophe below. The depth of the canyon at this point is 500 m. (Assume it drops off)

A) How long will it take the vehicle to impact the canyone bottom?

B) What will the vertical impact velocity be? Do you think they will survive, even with air bags?

Homework Equations



d = vit + 1/2at^2

d = (vi+vf)t
2

The Attempt at a Solution



d - 500m
ag = -9.81 m/s^2
vi = 0m/s
t =?

Since you can't solve for t, i solved for Vf.

Would the Vf be a negative number?

Then, i pluged the vi and vf into the 2nd equatioon above, but the answer i got was different from the answer given.
 
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Why can't you solve for t?
 
o wait, maybe i made a mistake.
 
I forgot that my Vi = 0 m/s therefore does not equate to a quadratic.
 
Well, use the first equation you wrote to solve for t. You know all the information you need to solve for part a.

The D = -500 m a = -g t=? and vi= 0 The reason why I say there is no initial velocity is because once the car goes over the edge and starts to fall, it's in free fall. The car may have HORIZONTAL velocity, but there is no initial vertical velocity.

Use that information and you can solve for v final.
 
Even if it's quadratic, why wouldn't you be able to solve for t?
 

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