What are the multiple solutions for sin x = 2/pi?

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SUMMARY

The equation sin x = 2/π has multiple solutions due to the periodic nature of the sine function. The principal solution is found using the inverse sine function, yielding x = sin-1(2/π) ≈ 0.69. Additional solutions can be derived using the periodicity of sine, specifically x = nπ + (-1)n * sin-1(2/π), where n is any integer. For instance, x = 2.451 is a valid solution outside the principal range.

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Sin x = 2/pi

How do you solve for x?? I am drawing a blank!

I did sin-1 ( 2/pi) = 0.69 but I need another value cause I am also supposed to get 2.451?
 
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sin(x) is periodic with period 2*pi. There are many solutions to sin(x)=2/pi. 2.451 is one of the 'other ones' outside of the range of sin^(-1). Draw a graph.
 

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