What Are the Odds of Winning Specific Prizes in Euromillions?

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SUMMARY

The discussion focuses on calculating the probabilities of winning specific prizes in the Euromillions lottery. The two events analyzed are event (A), where a player matches 2 "main" numbers and 1 "lucky star" number, and event (B), where a player matches 1 "main" number and 2 "lucky star" numbers. The calculated probabilities are 0.39 for event A and 0.37 for event B, indicating that event A is slightly more likely to occur. The calculations utilize the hypergeometric distribution to determine the odds based on the selection process of the lottery.

PREREQUISITES
  • Understanding of hypergeometric distribution
  • Knowledge of combinatorial mathematics, specifically "n choose k" calculations
  • Familiarity with probability theory and additive probability
  • Basic understanding of lottery mechanics and number selection
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  • Research hypergeometric distribution applications in probability theory
  • Learn about combinatorial calculations and their relevance in lottery odds
  • Explore the concept of independent events in probability
  • Study the Euromillions lottery rules and prize structure in detail
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Mathematicians, statisticians, lottery enthusiasts, and anyone interested in understanding the probabilities associated with lottery games like Euromillions.

mynameisfunk
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Homework Statement


Euromillions is a transnational lottery. A player selects 5 "main" numbers without replacement, ignoring order from 1 to 50. The player then selects 2 "lucky star" numbers without replacement and ignoring order from 1 to 11. Ultimately, 5 numbers are randomly selected without replacement ignoring order from 1 to 50 and independently, 2 numbers are selected without replacement from 1 to 11. Consider events (A) the player matches 2 "main" numbers and 1 "lucky star" number and (B) the player matches 1 "main" number and 2 "lucky star" numbers. Separately compute the probabilities of A & B. Which are more likely?


Homework Equations



Hyper geometric Distribution and additiive probability?

The Attempt at a Solution


Sorry for no latex, I couldn't seem to figure it out for the hypergeometric..

A: I had [(5 choose 2)*(45 choose 3)]/(50 choose 5) + [(2 choose 1)*(9 choose 1)]/(11 choose 2)=.39

B: I had [(5 choose 1)*(45 choose 4)]/(50 choose 5) + [(2 choose 2)*(9 choose 0)]/(11 choose 2)=.37


Not sure if this is right..
 
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mynameisfunk said:
A: I had [(5 choose 2)*(45 choose 3)]/(50 choose 5) + [(2 choose 1)*(9 choose 1)]/(11 choose 2)=.39
(Assuming the question means exactly 2 main numbers, etc., not at least 2...)
Not a bad start, but think again about how to combine the two probabilities. You want the probability of two independent events both happening.
 
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