What Are the PDFs for Transformed Variables in These Probability Distributions?

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SUMMARY

This discussion focuses on deriving the probability density functions (PDFs) for transformed variables from specific probability distributions. For a normal distribution X with parameters E(X) = 0 and V(X) = 16, the PDF for Y = e^X is derived using the transformation method. Additionally, the discussion addresses the Cauchy distribution, specifically finding the PDFs for Y = 1/(X^2) and Y = X^2. The standard method for deriving these PDFs involves calculating the cumulative distribution function (CDF) and differentiating it.

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1. If X is normal distributed with E(x) = 0 and V(x) = 16 or N(0,16) if you prefer, and Y = e^X, what is the pdf for Y [f(y)] for 0≤y

2. If X is a Cauchy Distribution: f(x) = 1/(π(1+x^2)) and Y = 1/(X^2), what is the pdf for y

3. Same as #2, but Y = X^2

Any help as well as an explanation would be great. Explanation doesn't have to be long as I feel like I'm close and understand the material fairly well, just need a little help.

Thanks!
 
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Standard method (for #1): P{Y <= y} = P{exp(X) <= y} = P{X <= ln(y)}, so the density of Y is f(y) = (d/dy)P{X <= ln(y)}, which you can evaluate.

The others are similar.

RGV
 

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