What are the resonant wavelengths?

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SUMMARY

The discussion centers on calculating the resonant wavelengths and lowest frequency for a pipe of length L, closed at one end and open at the other. The formula used is f = c/L, where c is the speed of sound in air, not the speed of light. For a pipe length of L = 5 meters, the calculated lowest frequency is 60 MHz. Participants emphasize the importance of understanding nodes and antinodes in relation to pipe resonance.

PREREQUISITES
  • Understanding of standing waves in pipes
  • Knowledge of nodes and antinodes
  • Familiarity with the speed of sound in air
  • Basic wave equations, specifically f = c/L
NEXT STEPS
  • Research the concept of acoustic resonance in tubes
  • Learn about the differences between closed-end and open-end pipes
  • Study the impact of pipe length on resonant frequencies
  • Explore diagrams illustrating standing waves and their characteristics
USEFUL FOR

Students studying wave mechanics, physics educators, and anyone interested in the principles of sound waves in pipes.

physics(L)10
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Homework Statement


Consider pipe of length L. The pipe is closed at one end and open at the other allowing a standing wave where a node exists at the closed end and a max exists at the open end.
a) what are the resonant wavelengths?
b) If L=5, what is the lowest frequency?


Homework Equations


f= c/L where c=speed of light, L=pipe length, f=frequency


The Attempt at a Solution



I think I got it right, I'm just looking for some confirmation and any other insight you may have for me.

a) L since it says the pipe length is L, it can't go any longer then that.

b) f=C/ L = 3*10^8/5= 0.6*10^8 Hz=60 Mega Hz
 
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physics(L)10 said:

Homework Statement


Consider pipe of length L. The pipe is closed at one end and open at the other allowing a standing wave where a node exists at the closed end and a max exists at the open end.
a) what are the resonant wavelengths?
b) If L=5, what is the lowest frequency?


Homework Equations


f= c/L where c=speed of light, L=pipe length, f=frequency


The Attempt at a Solution



I think I got it right, I'm just looking for some confirmation and any other insight you may have for me.

a) L since it says the pipe length is L, it can't go any longer then that.

b) f=C/ L = 3*10^8/5= 0.6*10^8 Hz=60 Mega Hz

Are you guys studying sound waves in pipes? If so, you don't need c, you need the speed of sound in air... Also did you discuss pipe lengths and how the nodes and antinodes produced by inteference cause resonance in the pipes if they are the proper length? You perhaps discussed tuning forks vibrating air in a pipe of some length? Anything familiar in what I have written?
 
Last edited:
pgardn said:
Are you guys studying sound waves in pipes? If so you don't need c, you need the speed of sound in air... Also did you discuss pipe lengths and how the nodes and antinodes produced by inteference cause resonance in the pipes if they are the proper length? You perhaps discussed tuning forks vibrating air in a pipe of some length? Anything familiar in what I have written?

We are just touching on basics of different waves, sound included. Yes we did touch a little on the nodes. No, we did not discuss tuning forks in a pipe.
 
physics(L)10 said:
We are just touching on basics of different waves, sound included. Yes we did touch a little on the nodes. No, we did not discuss tuning forks in a pipe.

Did you discuss the difference between closed at one end and open and both end pipes and sound? Because if you did not, its not easy to make sense of what you need to put in for L, the length of the pipe.
 
This might help. Read resonance of a air in a tube... I doubt you guys are using the end correction part... There are some nice diagrams that display the standing waves produced along with the nodes and antinodes in both types of tubes.

http://en.wikipedia.org/wiki/Acoustic_resonance

Im off for fishing...
 
I don't believe we did, but if you say that it wouldn't make sense if we didn't, then why would we be assigned this question? And it says that L=5 in part b.
 

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