What are the speeds and compression in a collision with a spring?

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SUMMARY

The discussion focuses on a physics problem involving a 100 g block attached to a spring with a spring constant (k) of 20 N/m and a 20 g ball thrown at 5.0 m/s. The participants analyze both perfectly elastic and perfectly inelastic collisions, emphasizing the use of conservation of momentum and energy equations. Key equations include the spring potential energy (Us = 0.5k(delta s)²) and kinetic energy (K = 0.5mv²). The conversation clarifies that potential energy in this context only pertains to the spring, not the mass of the block.

PREREQUISITES
  • Understanding of conservation of momentum
  • Knowledge of kinetic energy equations
  • Familiarity with spring potential energy calculations
  • Basic principles of elastic and inelastic collisions
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  • Study the principles of elastic and inelastic collisions in detail
  • Learn how to apply conservation of momentum in collision problems
  • Explore the calculations for maximum compression of springs
  • Investigate the effects of different spring constants on energy transfer
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This discussion is beneficial for physics students, educators, and anyone interested in understanding collision dynamics and energy conservation in mechanical systems.

loststudent0
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Homework Statement


A 100 g block on a frictionless table is firmly attached to one end of a spring with k = 20 N/m. The other end of the spring is anchored to the wall. A 20 g ball is thrown horiontally toward the block with a speed of 5.0 m/s.
a. If the collision is perfectly elastic, what is the ball's speed immediately after the collision?
b. What is the maximum compression of the spring?
c. Repeat parts a and b for the case of a perfectly inelastic collision.

Homework Equations


Us=.5k(delta s)2
K = .5mv2

The Attempt at a Solution


a. I'm thinking i have to use momentum of the ball.. but because of the spring, i guess i have to use energy equations..
Ki+Ui=Kf+Uf
but for some reason for the Ui, there is no place for me to put in the mass of the block since that is potential energy..do i need a mass?

i've found a thread that's the same..nm
https://www.physicsforums.com/showt...ed+direction+of+each+ball+after+the+collision
 
Last edited:
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loststudent0 said:
a. I'm thinking i have to use momentum of the ball.. but because of the spring, i guess i have to use energy equations..
Ki+Ui=Kf+Uf
To find the speed of the block after the collision, you'll need to apply both conservation of momentum and kinetic energy. For part (b) you'll need to consider spring potential energy.
but for some reason for the Ui, there is no place for me to put in the mass of the block since that is potential energy..do i need a mass?
Presumably the table is horizontal, so there are no changes in gravitational PE. The only PE you need to worry about is spring PE, which does not depend on mass.
 
Thank you for you guidance Doc Al..i think i understand now
 

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