What Are the Tensions in Two Blocks With Friction and Acceleration?

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SUMMARY

The discussion focuses on calculating the tensions in two strings connected to two blocks with masses m1=80 kg and m2=100 kg, experiencing a horizontal acceleration of 2 m/s² and a coefficient of friction of 0.14. The tension T2 in the string attached to m2 is calculated as 137.2 N, while the tension T1 in the string attached to m1 is determined to be 407 N. The solution involves applying Newton's second law and the frictional force equation, leading to a clear understanding of the forces acting on the system.

PREREQUISITES
  • Understanding of Newton's second law (Fnet=ma)
  • Knowledge of frictional force calculations (Ff=u(N))
  • Ability to analyze systems of connected masses
  • Familiarity with free body diagrams
NEXT STEPS
  • Study the derivation of tension in multi-body systems
  • Learn about the effects of varying coefficients of friction on tension
  • Explore advanced dynamics involving pulleys and multiple masses
  • Investigate the impact of acceleration on tension in different configurations
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding dynamics involving multiple masses and friction in mechanical systems.

Zywo
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Homework Statement


Two blocks of mass m1=80 kg and m2=100 kg and attached by a string, another sting comes off of mass m1 and is pulled horizontally (kinda looks like this) (T1 & T2 are tensions)
m2--T2--m1--T1--> there is a coefficient of friction u=.14 for both blocks, what is the tension in both strings while the system accelerates at 2 m/s^2?


Homework Equations


Fnet=ma
Ff=u(N)

The Attempt at a Solution


Ok so for m1 horizontal forces are T1 to the right, T2 to the left and friction.
T2=(100)(9.8)(.14)=137.2 N Friction for m1=(80)(9.8)(.14)=109.8
So T1-T2-Ff = m1*a therefore T1=(80)(2)+(109.8)+137.2= 407 N
Is this Correct??
Thanks!
 
Physics news on Phys.org
First consider the 2 block system as a 1 block system (combine their masses) then you can solve T1. Once you have this you can distribute T2 appropriately.
 

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