What Are the Threshold Kinetic Energies in Particle Decay Reactions?

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The discussion focuses on calculating the threshold kinetic energies for specific particle decay reactions involving pions and nucleons. The participants emphasize the need to apply conservation of momentum and energy principles, noting that the final state particles cannot all be at rest simultaneously due to momentum conservation. The equations provided by the teacher are crucial for solving the problem, particularly in determining the energy and momentum of the incident particles. There is a consensus that understanding the implications of threshold conditions is key to finding the correct kinetic energies. The thread highlights the complexity of the calculations and the necessity of careful consideration of the final momenta in the reactions.
nv125
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Electrodynamics and Relativity. Please Help!

Homework Statement



Consider the decay of a particle.

(a) Find the threshold kinetic energies of the incident particles in each of
the following reactions:

(i) ∏+ + p →∏++ ∏° + p
(ii) p + n →p + n + ∏° + ∏°

The incident particle is the first particle listed in the reactions; the target particle is at rest. The masses of the ∏+ and ∏° ions are 139.567MeV/c2 and 134.963 MeV/c2 respectively while the masses of the neutron and proton are respectively 939.566 MeV/c2 and 938.272 MeV/c2.




Homework Equations



The teacher suggested that I will need to use the following equations to get the solution
(Here P is the momentum and Px is the momentum of the incident particle ∏+in the X direction, assuming it hits the target particle p(proton) horizontally, so no P(momentum) in y or z direction)

ƩPiu=0

PuPu=m2c2= E2/C2-P2

Also said that using this notations will be useful to solve the problem

For ∏+, the incident particle:
Pu=(E/C, Px, 0, 0)
Pu=(E/C, -Px, 0, 0) where Px is the momentum of the incident particle, and no need to worry about y and z direction so just put zeros.


The Attempt at a Solution


This is what I have done so far to solve for part i, but I have no clue how to continue.
Since we are solving for the threshold kinetic energy, so assuming that ∏+, ∏° and p are at rest after the reaction.

(E/C, Px, 0, 0) +(mpC2, 0, 0, 0) - (m+C2,0, 0, 0 ) -(m∏°C2,0, 0, 0 ) - (mpC2,0, 0, 0 ) = 0

mp, m+, m∏° are just the rest mass.

PLEASE PLEASE help me to do this problem! thank you so much!
 
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nv125 said:
Since we are solving for the threshold kinetic energy, so assuming that ∏+, ∏° and p are at rest after the reaction.

(E/C, Px, 0, 0) +(mpC2, 0, 0, 0) - (m+C2,0, 0, 0 ) -(m∏°C2,0, 0, 0 ) - (mpC2,0, 0, 0 ) = 0

As you see, trying to have all 3 final state particles at rest is impossible due to conservation of momentum. You need to allow for some final momenta and then think about what being at threshold implies.
 
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