What Are the Units for Coulombs and Volts in Terms of m, kg, and s?

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SUMMARY

Coulombs and volts cannot be expressed solely in terms of the base SI units of meter (m), kilogram (kg), and second (s). The unit of electric charge, the coulomb (C), is defined as amperes (A) multiplied by seconds (s), represented as C = A · s. The volt (V), the unit of electric potential, is defined as kg·m²/(A·s³), indicating its dependence on mass, distance, and time, along with electric current.

PREREQUISITES
  • Understanding of SI base units: meter, kilogram, second, ampere
  • Basic knowledge of electrical units: coulomb and volt
  • Familiarity with dimensional analysis in physics
  • Concept of luminous intensity related to the candela
NEXT STEPS
  • Research the definition and applications of the ampere in electrical systems
  • Explore the relationship between energy, voltage, and current in circuits
  • Study the role of the candela in photometry and its relation to other SI units
  • Learn about dimensional analysis and its use in converting units in physics
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Students of physics, electrical engineers, and anyone interested in understanding the relationships between electrical units and their definitions in the SI system.

cemar.
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Im just curious what the units are for coulombs and volts in m kg and s.
 
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You cannot represent coulombs or volts in terms of only m, kg, and s. The SI system has seven base units (meter, kilogram, second, ampere, kelvin, mole, and candela).

In terms of these base units:

C = A \cdot s

V = \frac{ kg \cdot m^2 }{ A \cdot s^3 }

- Warren
 
Slightly off topic
Is the Candela still a base unit ?

"The candela is the luminous intensity, in a given direction, of a source that emits monochromatic radiation of frequency 540 x 10^12 hertz and that has a radiant intensity in that direction of 1/683 watt per steradian."

Sounds like you could define it in terms of energy / length?
 

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