What are the units of A and δ in Dirac's delta function?

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In the discussion about the units of A and δ in Dirac's delta function, it is established that the delta function, δ(τ), has dimensions that are the reciprocal of the variable of integration, making it dimensionless when multiplied by its differential, dτ. Consequently, since E is measured in Joules, the unit of A must also be Joules to maintain dimensional consistency in the equation E = ∫ Aδ(τ) dτ. The reasoning is supported by the property of the delta function, which integrates to one over its variable. This confirms that A and E share the same unit of measurement. Understanding these units is crucial for proper application in physics and engineering contexts.
Gonzolo
Consider :

E = \int P(\tau) d\tau = \int A\delta(\tau) d\tau

E is in Joules and P(\tau) is in Watts, what are the units of A? What about \delta?

I have a hunch, but need to have all doubts removed.
 
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The delta function has the dimension of the reciprocal of the variable of integration. Thus delta(tau)d(tau) is non-dimensional. Therefore A has the same dimension as E, i.e. Joules.
 
And you can see why the dirac delta has units of the reciprocal of the integration variable from

\int _{-\infty} ^{\infty} \delta (p-p_0) dp = 1,
where p is any parameter.
 
Thanks guys!
 
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