What are the values of a and b for the given density function if E(X)=-1?

Click For Summary
The discussion focuses on finding the values of a and b for a given density function, given that the expectation E(X) equals -1. Participants emphasize the importance of using the equations for the expectation and the properties of probability density functions. The key equations involve integrating the density function f(x) over the interval to equal 1 and setting up the expectation integral to equal -1. Clarification is provided on how to relate the density function to these integrals. The conversation concludes with a participant expressing gratitude for the guidance received in understanding the problem.
snoggerT
Messages
183
Reaction score
0
Density Function and E(x)[solved]

The density function of X is given by

https://webwork.math.lsu.edu/webwork2_files/tmp/equations/48/83b2bf602cc895a007a673a9a23c3c1.png

If the expectation of X is E(X)=-1, find a and b.



The Attempt at a Solution



I'm actually working ahead of the class with this problem, so the material hasn't been covered, but I would like to figure it out. I know the equation for E(X), but don't know how to relate it to this problem. Please help.

E(X)=∫xf(x)dx
 
Last edited by a moderator:
Physics news on Phys.org
You have two unknowns a and b, and you are given two conditions. f(x) is a density so what does that tell you? And you know E(x) value. Write down those two equations and solve for the unknowns a and b.
 
LCKurtz said:
You have two unknowns a and b, and you are given two conditions. f(x) is a density so what does that tell you? And you know E(x) value. Write down those two equations and solve for the unknowns a and b.

- I haven't been able to figure it out with what you said. I know that the probability density function equation is the integral from a to b of f(x)dx, but I'm not sure how to relate that to the E(X) formula.
 
snoggerT said:
- I haven't been able to figure it out with what you said. I know that the probability density function equation is the integral from a to b of f(x)dx, but I'm not sure how to relate that to the E(X) formula.

No. The probability density function is not "the integral from a to b of f(x)dx". The probability density function is f(x). But what do you know about probability density functions and their integrals? That will give you one equation in a and b. And the integral for E(x) = -1 will give you another.
 
You must have
\int_0^1 xf(x)dx= E(x)
and
\int_0^1 f(x) dx= 1

Actually do those integrals with f(x)= a+ bx and solve the two equations for a and b.
 
HallsofIvy said:
You must have
\int_0^1 xf(x)dx= E(x)
and
\int_0^1 f(x) dx= 1

Actually do those integrals with f(x)= a+ bx and solve the two equations for a and b.

- Thanks. I wasn't quite grasping what i was being told at first, but as soon as you put both equations up, I knew what to do.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

Similar threads

  • · Replies 19 ·
Replies
19
Views
4K
  • · Replies 3 ·
Replies
3
Views
1K
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 18 ·
Replies
18
Views
3K