What are the x and y intercepts y= x+2/x-7 rational

  • #1
what are the x and y intercepts

y= x+2/x-7

rational expression

is y=-2/7
and x= -2
 

Answers and Replies

  • #2
1,631
4


you find x intercepts by letting y=0, and y intercepts by letting x=0.
 
  • #3
537
3


you find x intercepts by letting y=0, and y intercepts by letting x=0.

That is the general approach to these problems, but notice that the function is not defined at x=0.

What do you think this means jeahomgrajan? How would you go about finding the x-intercept, i.e. setting y=0 as sutupidmath mentioned and then solving for x?
 
  • #4
1,631
4


That is the general approach to these problems, but notice that the function is not defined at x=0.
i interpreted the function as:


[tex]y=x+\frac{2}{x-7}[/tex]
 
  • #5
537
3


i interpreted the function as:
[tex]y=x+\frac{2}{x-7}[/tex]

I see. Gotcha :) Gotta love [itex]\LaTeX[/itex].
 
  • #6
symbolipoint
Homework Helper
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The original equation as written means exactly:

y = x + [tex]\frac{2}{x}[/tex] - 7
 
  • #7
537
3


The original equation as written means exactly:

y = x + [tex]\frac{2}{x}[/tex] - 7

We know that. sutupidmath misread the original equation, and that's what that post was about. Please see my original post jeahomgrajan.
 
  • #8
HallsofIvy
Science Advisor
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What was originally written would be strictly interpreted as
[tex]y= x+ \frac{2}{x}-7[/tex]
But, considering how many people just hate to use parentheses, it could also be interpreted as "x+ 2/(x- 7)"
[tex]y= x+ \frac{2}{x- 7}[/tex]
or even as "(x+2)/(x- 7)"
[tex]y= \frac{x+ 2}{x- 7}[/tex]

Unfortunately, jeahomgrajan hasn't got back to say which he/she meant, but the fact that he/she suggested y= -2/7 and x= -2 as intercepts suggests what sutupidmath assumed was meant.
 

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