- #1

- 49

- 0

what are the x and y intercepts

y= x+2/x-7

rational expression

is y=-2/7

and x= -2

y= x+2/x-7

rational expression

is y=-2/7

and x= -2

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- Thread starter jeahomgrajan
- Start date

- #1

- 49

- 0

what are the x and y intercepts

y= x+2/x-7

rational expression

is y=-2/7

and x= -2

y= x+2/x-7

rational expression

is y=-2/7

and x= -2

- #2

- 1,631

- 4

you find x intercepts by letting y=0, and y intercepts by letting x=0.

- #3

- 537

- 3

you find x intercepts by letting y=0, and y intercepts by letting x=0.

That is the general approach to these problems, but notice that the function is not defined at x=0.

What do you think this means jeahomgrajan? How would you go about finding the x-intercept, i.e. setting y=0 as sutupidmath mentioned and then solving for x?

- #4

- 1,631

- 4

i interpreted the function as:That is the general approach to these problems, but notice that the function is not defined at x=0.

[tex]y=x+\frac{2}{x-7}[/tex]

- #5

- 537

- 3

i interpreted the function as:

[tex]y=x+\frac{2}{x-7}[/tex]

I see. Gotcha :) Gotta love [itex]\LaTeX[/itex].

- #6

symbolipoint

Homework Helper

Education Advisor

Gold Member

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The original equation as written means exactly:

y = x + [tex]\frac{2}{x}[/tex] - 7

- #7

- 537

- 3

The original equation as written means exactly:

y = x + [tex]\frac{2}{x}[/tex] - 7

We know that. sutupidmath misread the original equation, and that's what that post was about. Please see my original post jeahomgrajan.

- #8

HallsofIvy

Science Advisor

Homework Helper

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What was originally written would be strictly interpreted as

[tex]y= x+ \frac{2}{x}-7[/tex]

But, considering how many people just

[tex]y= x+ \frac{2}{x- 7}[/tex]

or even as "(x+2)/(x- 7)"

[tex]y= \frac{x+ 2}{x- 7}[/tex]

Unfortunately, jeahomgrajan hasn't got back to say which he/she meant, but the fact that he/she suggested y= -2/7 and x= -2 as intercepts suggests what sutupidmath assumed was meant.

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