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What are the x and y intercepts y= x+2/x-7 rational

  1. Apr 7, 2009 #1
    what are the x and y intercepts

    y= x+2/x-7

    rational expression

    is y=-2/7
    and x= -2
     
  2. jcsd
  3. Apr 8, 2009 #2
    Re: Intercepts

    you find x intercepts by letting y=0, and y intercepts by letting x=0.
     
  4. Apr 8, 2009 #3
    Re: Intercepts

    That is the general approach to these problems, but notice that the function is not defined at x=0.

    What do you think this means jeahomgrajan? How would you go about finding the x-intercept, i.e. setting y=0 as sutupidmath mentioned and then solving for x?
     
  5. Apr 8, 2009 #4
    Re: Intercepts

    i interpreted the function as:


    [tex]y=x+\frac{2}{x-7}[/tex]
     
  6. Apr 8, 2009 #5
    Re: Intercepts

    I see. Gotcha :) Gotta love [itex]\LaTeX[/itex].
     
  7. Apr 8, 2009 #6

    symbolipoint

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    Re: Intercepts

    The original equation as written means exactly:

    y = x + [tex]\frac{2}{x}[/tex] - 7
     
  8. Apr 8, 2009 #7
    Re: Intercepts

    We know that. sutupidmath misread the original equation, and that's what that post was about. Please see my original post jeahomgrajan.
     
  9. Apr 8, 2009 #8

    HallsofIvy

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    Re: Intercepts

    What was originally written would be strictly interpreted as
    [tex]y= x+ \frac{2}{x}-7[/tex]
    But, considering how many people just hate to use parentheses, it could also be interpreted as "x+ 2/(x- 7)"
    [tex]y= x+ \frac{2}{x- 7}[/tex]
    or even as "(x+2)/(x- 7)"
    [tex]y= \frac{x+ 2}{x- 7}[/tex]

    Unfortunately, jeahomgrajan hasn't got back to say which he/she meant, but the fact that he/she suggested y= -2/7 and x= -2 as intercepts suggests what sutupidmath assumed was meant.
     
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