What Bandgap Energy Range is Required for Blue LEDs?

Click For Summary

Homework Help Overview

The discussion centers around determining the bandgap energy range required for blue LEDs, specifically relating to the wavelengths of blue light and their corresponding energy values in electron volts (eV).

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster seeks guidance on how to relate the wavelength of blue light to the bandgap energy of semiconductors, expressing confusion about the concept of bandgap energies.
  • Participants provide relevant equations that relate frequency, velocity, and wavelength, indicating a focus on the mathematical relationships involved.

Discussion Status

Participants are actively sharing equations and clarifying concepts related to frequency and wavelength. There is an ongoing exploration of how these equations apply to the problem at hand, but no consensus or resolution has been reached yet.

Contextual Notes

The original poster has indicated a lack of understanding regarding bandgap energies, which may affect their ability to engage with the problem fully. The discussion includes attempts to clarify the necessary equations without providing direct solutions.

aChordate
Messages
76
Reaction score
0

Homework Statement



Blue light corresponds to free space wavelengths of approximately 450 to 495 nm. If we want to use a semiconductor to make a blue LED, what range of energies must the semiconductor's bandgap fall within? Express your answer in units of electron volts(eV). What is an example of a real semiconductor with a bandgap in this range?


Homework Equations



?

The Attempt at a Solution




Can someone lead me in the right direction? From what I've read, blue light LED are high energy and the whole notion of bandgap energies confuses me.
 
Physics news on Phys.org
Relevant Equations..

Frequency = velocity * wavelength
Energy = Planck const * frequency
 
CWatters said:
Relevant Equations..

Frequency = velocity * wavelength

Frequency = speed / wavelength

ehild
 
Oops yes that's right.

Velocity = frequency * wavelength
so
frequency = Velocity/wavelength
 

Similar threads

"From your data, is the bandgap of ZnSe direct or indirect?"
  • · Replies 6 ·
Replies
6
Views
4K
Hydrogen Emission Spectrum and Electron Energy Levels
  • · Replies 2 ·
Replies
2
Views
2K
How does Band Gap and Refractive index relate to Wavelength?
  • · Replies 2 ·
Replies
2
Views
2K
Engineering What Is the Bandgap of a Semiconductor with Light Emission at 326.3 nm?
  • · Replies 1 ·
Replies
1
Views
2K
Undergrad Bandgap Energy and refractive index
  • · Replies 1 ·
Replies
1
Views
2K
Undergrad Luminous Fast Blue Optical Transients (LFBOTs)
  • · Replies 0 ·
Replies
0
Views
974
Calculating Stopping Potential in Photoelectric Effect Experiment
  • · Replies 4 ·
Replies
4
Views
2K
Peak wavelength and Spectral Bandwidth
  • · Replies 4 ·
Replies
4
Views
2K
Undergrad Why orange color is visible with blue LED?
  • · Replies 11 ·
Replies
11
Views
3K
Undergrad Blue lights (LEDs) consume more power than red (and green)?
  • · Replies 25 ·
Replies
25
Views
31K