Calculating Stopping Potential in Photoelectric Effect Experiment

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Homework Help Overview

The discussion revolves around a photoelectric effect experiment where the stopping potential is measured and its relationship with different wavelengths of light is questioned. The original poster is trying to understand the concept of stopping potential in the context of energy units and voltage.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to relate stopping potential to energy units, expressing confusion over the use of eV for a potential measurement. Some participants question the appropriateness of using eV instead of volts for stopping potential.

Discussion Status

The discussion is exploring the terminology and units used in the context of stopping potential. Participants are providing insights on the relationship between energy and potential, with some suggesting that the question may be misleading in its use of units.

Contextual Notes

There is an ongoing discussion about the correct units for stopping potential, with some participants noting that the question may not align with standard conventions in physics regarding voltage and energy measurements.

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Homework Statement


In a photoelectric experiment, a stopping potential of 2.70 eV is measured when ultraviolet light of wavelength 380 nm is incident on the metal. If blue light of wavelength 440 nm is used, what is the new stopping potential in eV?

Homework Equations

The Attempt at a Solution


I think i understand how to do this problem (qV = hc/λ - work function) but am very confused as they have given and ask for the stopping potential in eV. I thought that eV was a unit of energy and that stopping potential (as it is a voltage) is given by the units V. How can the units of a potential be eV?
 
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You're right. The stopping potential should really be measured in V, not eV. But since it is electrons you are stopping, people sometimes get sloppy and refer to electron energy (in eV) rather than the potential (in V).
 
So i should give the answer for the energy and not the potential?
 
The numerical results should be the same. I would five the answer in V, and explain that the question is really incorrect, since potentials are measured in V.
 
ok thank you very much!
 

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