What Causes Tension in a Whirling Rope?

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    Rope Tension
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SUMMARY

The discussion focuses on the tension in a uniform rope of length L and mass m, whirled in a horizontal circle with angular velocity ω. The tension at a point on the rope, located a distance r from the held end, is derived using Newton's second law in radial form. The centripetal force required for circular motion at that point is provided by the tension, which increases along the length of the rope due to the mass of the rope segment outside that point. This understanding clarifies the relationship between tension and centripetal acceleration in a rotating system.

PREREQUISITES
  • Understanding of Newton's second law of motion
  • Familiarity with centripetal acceleration concepts
  • Knowledge of uniform mass distribution in physical systems
  • Basic principles of circular motion
NEXT STEPS
  • Study the derivation of tension in rotating systems using Newton's laws
  • Explore the effects of varying angular velocity on tension in a rope
  • Learn about the dynamics of circular motion in non-uniform mass distributions
  • Investigate real-world applications of tension in rotating ropes or cables
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Physics students, educators, and anyone interested in understanding the mechanics of tension in rotating systems.

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Homework Statement


A uniform rope with length L and mass m is held at one end and whirled in a horizontal circle with angular velocity ω.


Homework Equations


At a point on the rope a distance r from the end that is held what is the tension F?


The Attempt at a Solution


Clearly the Newtons second law in radial form should be used. I do not really understand what causes the tension. Imagine a point on the rope a distance r from the end that is held. At this point there is a force directed to the center of the circle because of centripetal acceleration, also the rest of the rope accelerates away from the center of the circle and tends to pull the point?
 
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At any point on the rope, the part outside has to be kept in a circular motion: this requires a force, identical to the tension at that point.
 

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