What Determines the Velocity of a Baseball After Being Hit?

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    Impulse Momentum
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SUMMARY

The discussion focuses on calculating the velocity of a baseball after being hit by a bat and the subsequent momentum changes in a collision scenario involving Olaf catching a ball. The impulse applied to the baseball is -8.4 N*s, leading to a misunderstanding of the relationship between impulse and momentum. The correct approach involves recognizing that impulse equals the change in momentum, which is crucial for solving both problems presented. The final velocities calculated for both scenarios are 57.9 m/s for the baseball and 5.90 cm/s for Olaf after the collision.

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Homework Statement



My question is:
Now assume that the pitcher in Part D throws a 0.145 kg baseball parallel to the ground with a speed of 32 m/s in the +x direction. The batter then hits the ball so it goes directly back to the pitcher along the same straight line. What is the ball's velocity just after leaving the bat if the bat applies an impulse of -8.4 N*s to the baseball?


Homework Equations



The first part of the question is this:
Assume that a pitcher throws a baseball so that it travels in a straight line parallel to the ground. The batter then hits the ball so it goes directly back to the pitcher along the same straight line. Define the direction the pitcher originally throws the ball as the +x direction.
The right answer (that I got correct) is this:
The impulse on the ball caused by the bat will be in the negative x direction.

The Attempt at a Solution


Well I know that impulse is just the change in momentum...
So I did
mv=mv
8.4 N*s=(0.145)(v)
and I got 57.9 m/s... which was wrong

AND ONE MORE QUESTION PLEASE...

Homework Statement



My question is:
Olaf is standing on a sheet of ice that covers the football stadium parking lot in Buffalo, New York; there is negligible friction between his feet and the ice. A friend throws Olaf a ball of mass 0.400 kg that is traveling horizontally at 10.9 m/s. Olaf's mass is 73.5 kg.
If the ball hits Olaf and bounces off his chest horizontally at 7.30 m/s in the opposite direction, what is his speed vf after the collision?


Homework Equations



The first part of the question is:
If Olaf catches the ball, with what speed v_f do Olaf and the ball move afterward?
I got 5.90 cm/s, which is right.

The Attempt at a Solution


I found the initial momentum which is (-7.3 m/s * 100cm/1m)(0.400 kg) = -292 kgcm/s
And this was right

And then I tried momentum final = mv
-292 = (73.5kg)(v)
And it was wrong...
 
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For the first problem: Impulse is equal to the change in momentum, not the momentum...

For the second problem: I don't see you trying to set up the problem correctly. Initially, the momentum of the system is all in the ball (that momentum would be equal to the mass of the ball times the velocity of the ball). After the collision, both the ball and Olaf are moving, so the total momentum would be the sum of the ball's momentum (its mass times velocity) and Olaf's (his mass times velocity; his velocity is what you are solving for).
 

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