Baseball change of direction Force and Impulse

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SUMMARY

The discussion focuses on calculating the impulse and average force exerted on a softball during a collision with a bat. The mass of the softball is 0.4 kg, pitched at a speed of 24 m/s, and hit back at 20 m/s. The impulse imparted on the ball is calculated as 18 Ns, while the average force exerted by the bat on the ball is determined to be 1200 N over a contact time of 0.015 seconds. The initial calculation mistakenly used 25 m/s instead of the correct 24 m/s for the pitch speed.

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physicsballer2
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A softball of mass .4kg is pitched at a speed of 24 m/sec, the batter hits it back directly at the pitcher at a speed of 20 m/s. The bat acts on the ball for .015 secs. A: What is the impulse imparted on the ball? B: What is the average force exerted by the bat on the ball?

pi= mv pi= (.4)(25)= 10

pf=mv pf= (.4)(20)= 8

F=Δp/t =10-(-8 )/ .015 = 1200 N
I= Δp = 18 NS

Is this right?
 
Last edited:
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change 25 to 24 per the problem
 
physicsballer2 said:
A softball of mass .4kg is pitched at a speed of 24 m/sec, the batter hits it back directly at the pitcher at a speed of 20 m/s. The bat acts on the ball for .015 secs. A: What is the impulse imparted on the ball? B: What is the average force exerted by the bat on the ball?

pi= mv pi= (.4)(25)= 10

pf=mv pf= (.4)(20)= 8

F=Δp/t =10-(-8 )/ .015 = 1200 N
I= Δp = 18 NS

Is this right?

Almost. You used 25 m/s when it's 24 m/s. You did part B before part A. Otherwise OK.
 

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