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Baseball change of direction Force and Impulse

  1. May 23, 2013 #1
    A softball of mass .4kg is pitched at a speed of 24 m/sec, the batter hits it back directly at the pitcher at a speed of 20 m/s. The bat acts on the ball for .015 secs. A: What is the impulse imparted on the ball? B: What is the average force exerted by the bat on the ball?

    pi= mv pi= (.4)(25)= 10

    pf=mv pf= (.4)(20)= 8

    F=Δp/t =10-(-8 )/ .015 = 1200 N
    I= Δp = 18 NS

    Is this right?
     
    Last edited: May 23, 2013
  2. jcsd
  3. May 23, 2013 #2
    change 25 to 24 per the problem
     
  4. May 23, 2013 #3

    rude man

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    Almost. You used 25 m/s when it's 24 m/s. You did part B before part A. Otherwise OK.
     
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