What Direction Does the Coil Rotate in a Magnetic Field?

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SUMMARY

The discussion focuses on the rotation direction of a circular coil with a radius of 10 cm and 25 turns in a magnetic field of strength 2.4 T. The coil's axis of rotation is perpendicular to the magnetic field, which points down the page. The induced voltage calculated is 5.92 V, and the rotation direction is determined using the Lorentz force and the right-hand rule. The consensus is that the coil rotates counterclockwise when viewed from above.

PREREQUISITES
  • Understanding of Faraday's Law of electromagnetic induction
  • Familiarity with the Lorentz force and its application to current-carrying conductors
  • Knowledge of magnetic flux and its calculation
  • Ability to apply the right-hand rule for determining rotational direction in magnetic fields
NEXT STEPS
  • Study the application of Faraday's Law in different electromagnetic scenarios
  • Learn about the right-hand rule and its implications in electromagnetism
  • Explore the concept of torque on loops of wire in magnetic fields
  • Investigate the effects of varying magnetic fields on induced voltage
USEFUL FOR

Students of physics, electrical engineers, and anyone interested in understanding the principles of electromagnetism and the behavior of coils in magnetic fields.

Darth Geek
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Homework Statement



A circular coil, with radius of 10 cm, and 25 turns, rotates in a constant magnetic field of
strength 2.4 T, with the axis of rotation perpendicular to the direction of the magnetic
field.

(a question about finding the induced voltage- 5.92 V)

part C. If the magnetic field that the coil is in points down the page, which direction
does the coil rotate? Answer for both cases: (1) q traveling from left to right
and (2) q traveling from right to left in the coil. (Draw a diagram to help you.)

Homework Equations



Torque on a loop of wire in a magnetic field: τ = I · A · B · sinθ

Magnetic flux: φ = B · A · cosθ

Induced potential difference (emf)
due to a changing magnetic field: V = -N · ∆φ/∆t

The Attempt at a Solution



I really have no idea how to start this one, since the oh-so helpful Apex (Not) Learning doesn't give me any information about this, instead restating essentially the same Faraday's Law problem throughout the 'notes'. I'm not even sure my original answer concerning the voltage is correct, since there is no area facing the B-field and therefore negligible flux.

I've thought of using the Lorentz Force and saying that the loop rotates out of the page, but the problem seems to imply that it is (counter)clockwise in the page.
 
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Darth Geek said:

Homework Statement



A circular coil, with radius of 10 cm, and 25 turns, rotates in a constant magnetic field of
strength 2.4 T, with the axis of rotation perpendicular to the direction of the magnetic
field.

(a question about finding the induced voltage- 5.92 V)

part C. If the magnetic field that the coil is in points down the page, which direction
does the coil rotate? Answer for both cases: (1) q traveling from left to right
and (2) q traveling from right to left in the coil. (Draw a diagram to help you.)

Homework Equations



Torque on a loop of wire in a magnetic field: τ = I · A · B · sinθ

Magnetic flux: φ = B · A · cosθ

Induced potential difference (emf)
due to a changing magnetic field: V = -N · ∆φ/∆t

The Attempt at a Solution



I really have no idea how to start this one, since the oh-so helpful Apex (Not) Learning doesn't give me any information about this, instead restating essentially the same Faraday's Law problem throughout the 'notes'. I'm not even sure my original answer concerning the voltage is correct, since there is no area facing the B-field and therefore negligible flux.

I've thought of using the Lorentz Force and saying that the loop rotates out of the page, but the problem seems to imply that it is (counter)clockwise in the page.

This is a Lorentz force problem for a current carrying conductor in a magnetic field. You can use the right hand rule or you can work it out: The Lorentz force is a cross product of what two vectors? Take a small length of the coil 90 deg. from the axis. What is the direction of the cross product vector? Then take a small section of the coil diametrically opposite. What is the direction of the Lorentz force? That will tell you how it will rotate.

AM
 

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