What distance does the block slide?

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    Block Slide
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Homework Help Overview

The discussion revolves around a physics problem involving the motion of a block, specifically focusing on the distance it slides. The subject area includes concepts from mechanics, particularly energy conservation and kinematics.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss various equations related to energy and motion, including kinetic and potential energy. There are attempts to clarify the correct application of trigonometric functions and coefficients of friction in the context of the problem. Some participants express confusion about their calculations and seek validation of their approaches.

Discussion Status

Several participants are exploring different interpretations of the equations involved and questioning the assumptions made in their calculations. There is an ongoing exchange of ideas, with some suggesting modifications to the equations used, but no consensus has been reached on the correct approach or solution.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information available for solving the problem. There is also a focus on ensuring that the assumptions about angles and forces are correctly applied in their reasoning.

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Homework Statement


upload_2016-5-24_16-24-33.png


Homework Equations


m*v^2 / 2 and k*x^2 / 2 and 0,5*m*v^2

The Attempt at a Solution


[/B]
in task a I got correct answer there v = 20 m/s
in task b I got wrong answer I got the distance = 0,76 m but I should be 32 m

here is my answer :
0,5*m*(sin(30)*v) - mu * m*g*cos(30) = m*g*h
h=0,38 m
sin (30) = h/L there L is the distance of the block when it goes up
L= h/sin(30) = 0,76

What I do wrong in task b ?

Thanks

 
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JiJiasd said:
0,5*m*(sin(30)*v)
sin(30)v should be squared
 
I seem to get the answer on the second one to be 35.4012435624
 
JiJiasd said:
mu * m*g*cos(30)
Shouldnt this be mu*(m*g*cos(30))*h/cos(30)=mu*m*g*h?
I think so...
 
sidt36 said:
I seem to get the answer on the second one to be 35.4012435624
What equation you did use ? thanks
 
Replusz said:
sin(30)v should be squared
I tried with 0,5*m*(sin(30)*v)^2 - mu * m*g*cos(30) = m*g*h
but it does not give me the correct answer
thanks
 
Replusz said:
Shouldnt this be mu*(m*g*cos(30))*h/cos(30)=mu*m*g*h?
I think so...
Now I tried 0,5*m*(sin(30)*v)^2 - mu * m*g*cos(30) *h/sin(30) = m*g*h
but not working
 
I used a kinematics equation
 

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