What do dB and dt represent in Faraday's law equation?

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matthewgill
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Hello,

I have found this information on the internet, but just need a few parts explained:

http://hyperphysics.phy-astr.gsu.edu/Hbase/electric/farlaw.html

For the 'magnet moving into coil' (lower left illustration),where it says ^B/^t=0.4T/s (where '^' is the triangular symbol in the illustration) what do i have to replace the '^B' and '^t' with for my own equation?

Thank you
 
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matthewgill said:
Hello,

I have found this information on the internet, but just need a few parts explained:

http://hyperphysics.phy-astr.gsu.edu/Hbase/electric/farlaw.html

For the 'magnet moving into coil' (lower left illustration),where it says ^B/^t=0.4T/s (where '^' is the triangular symbol in the illustration) what do i have to replace the '^B' and '^t' with for my own equation?

Thank you

"^" is nothing but the change..^ can be replaced with "d" differentiation. To explain with other example, velocity is the change in distance w.r.t time.
i.e. velocity = final distance - initial distance/time taken
which can be written as velocity = dl/dt where dl is the change in distance ...

The same applies for faraday's law
^B/^t = d(BA)/dt= change in magnetic flux w.r.t. time..where B is magnetic field and A is area

For more details see
http://en.wikipedia.org/wiki/Electromagnetic_induction