You raise a number of important and interesting points... far more interesting than the lab reports I should probably be grading instead of writing this! =)
stevendaryl said:
If the particles don't affect the wave function, and the only thing that affects the particles is the wave function, then the particles aren't really participants in the physics.
Now this is a very strange statement. I think it reflects a view which your other comments also seem to reflect -- namely that you are accustomed (from ordinary QM or whatever) to thinking of the wave function as the thing where, so to speak, "the action is". So to you, if the wave function of a particle is split in half, with part in LA and part in NY, then there's going to be a 50/50 chance of detecting it in LA/NY, according to all the usual QM rules. And then you assume that this is still the case in Bohm's theory, such that the "real particle position" that supplements the wf is a kind of pointless epiphenomenon that "doesn't participate in the physics". If you want to understand the Bohm theory, though, you have to accept that it just doesn't work this way. You have to retrain yourself to think in a different way. In particular, you have to accept that the physical stuff we interact with in real life (particles, brick walls, balls, apparatus pointers, etc.) is not "made of" wave function, but is instead made of particles. This is hard for people to even understand as an option, because in ordinary QM (which everyone always learns first), there is only the one thing -- the wave function -- so *of course* that is where all the physics is. But in Bohm's theory there are really *two* things, the wave *and* the particle. So there is a legitimate and meaningful and important question: which one are things like tables and chairs made of? And the answer (that you have to provisionally accept if you want to understand the Bohmian view of the world at all) is that stuff is made of *particles*. Despite what the traditional terminology suggests, it's actually the *wave function* that is the "hidden variable" in Bohm's theory -- the particles are right there, visible, in front of your eyes when you look out on and interact physically with the world; whereas the wave function is this spooky ethereal invisible thing that is sort of magically acting behind the scenes to make the particles move the way they move.
That's the overview point. Now let me try to explain exactly how some of your comments exhibit this confusion about how to understand the "roles" of the two things, the wave and the particles...
I know that the usual way of doing one-particle Bohmian mechanics has an ordinary Newtonian-type force term, and then an additional term due to the "quantum potential", which can be viewed as a small correction to the Newtonian prediction. But in the actual world, there is no "external" potential, there is only interactions with other particles. So a many-particle analog to the quantum potential is all there is to affect particle trajectories.
This is really an aside, but actually the "usual way of doing ... bohmian mechanics" does *not* involve any "quantum potential". Yes, Bohm and a few others like to formulate the theory that way, as was discussed in the thread above. But (I think at least) it is much better (and certainly these days more standard) to forget the silly quantum potential, and just let the ordinary wave function be the thing that "guides" or "pilots" the particles. The quantum potential is a big bloated pointless middle man, at best. Better to just get rid of it and define the theory in terms of (a) the wave function obeying the usual Sch eq, and (b) the particles obeying the guidance law, basically v = j/rho (where j and rho are what are usually called the probability current and density respectively).
No, I think I understand exactly why MWI is conceptually a nightmare, when it comes to understanding the relationship between theory and experience. But I don't think a "pilot wave" theory is any better. It just supplements the universal wave function with particles that carry out a pantomime of actual physical interactions.
Here you assume that the "actual physical interactions" are happening in the wave function, so that the particles are (at best) pantomiming some one small part of the physics. But that's not the right way to think about it. If what we mean by "physical" is stuff like balls crashing into brick walls, then that is particles. What you call a ball or a brick wall is, in bohm's theory, a collection of *particles*.
Suppose you arrange a bunch of atoms into a solid brick wall. Then a Bohmian type of theory would predict that the wall would continue to exist for a good long time afterward, giving a reassuring sense of solidity. But now, you take a baseball (another clump of atoms arranged in a particular pattern) and throw it at the wall. What happens then?
It'll bounce off the wall. The theory predicts this. Here is how to think about it. Pretend the brick wall and the ball are each just single particles, and assume that they have an interaction potential which is basically zero for r>R, and basically infinite for r<R. Call the wall's coordinate "x" and the ball's "y". The configuration space is now the x-y plane. Suppose the wall is initially at rest near x=0, i.e., its initial wf is some sharply peaked stationary packet centered on x=0. The ball starts at some negative value of y, say -L, and has a positive velocity; so take its initial wf to be an appropriate packet. Now the wave function for the 2 particle system -- which we assume is a product state of the two one-particle wf's just described -- is thus a little packet located at (x=0, y=-L) and moving with some group velocity toward the origin (x=0, y=0). What Schroedinger's equation says now is that the packet (in the 2d config space) will propagate up, bounce off the big potential wall at (x=0,y=0), and reflect back down. (I assume here that the mass of the wall particle is large compared to the mass of the ball particle.) So much for the wave function.
What about the actual/bohmian particle positions? Well, at t=0, the wall has some actual position in the support of its wf, and likewise for the ball. And then the actual configuration point just moves along with the moving/bouncing packet in configuration space. So the story you'd tell about the two particles in real space is: the wall particle just sits there the whole time, while the ball particle comes toward it, bounces off, and heads away.
Now you want to ask: what happens if, instead of initially being in a (near) position eigenstate, the wall is initially in a superposition of two places? It's a good question, but if you think it through carefully, you'll find that the theory says exactly what anybody would consider the right/reasonable thing. So, just recapitulate the above, but now with the initial wf for the wall being a sum of two packets, one peaked at x=0 and one peaked at x=D. Now (I'm picturing all of this playing out in the x-y plane, and hopefully you are too) the initial 2-particle wave function in the 2D config space has *two* lumps: one at (x=0, y=-L), and the other at (x=D, y=-L). So then run the wf forward in time using the sch eq: the two lumps each propagate "upward" (i.e., in the y-direction). Eventually the first lump reaches the potential wall near (x=0,y=0) and bounces back down. Meanwhile the other lump continues to propagate up until it reaches the potential wall near (x=D,y=D) at which point it too reflects and starts propagating back down. So much for the wave function.
What about the particles? The point here is that in bohm's theory the *actual configuration* is in one, or the other, of the two initial lumps. If (by chance) it happens to be in the first lump, then the story is *exactly* as it was previously -- the other, "empty" part of the wave function (corresponding to the wall having been at x=D) is simply irrelevant. It plays no role whatever and could just as well have been dropped. On the other hand, if (by chance) the actual positions are initially in the second lump, then the story (of the particles) is as follows: the ball propagates toward the wall (which is at x=D) until the ball gets to x=D, and then it bounces off. That is, there is some fact of the matter about where the wall actually is, and the ball bounces off the wall just as one would expect it to.
The only thing that could possibly confuse anybody about this is that they are thinking: but the wall really *isn't* in one or the other of the definite places, x=0 or x=D, it's in a *superposition* of both! Indeed, that's what you'd say in ordinary QM. And then you'd have to make up some story about how throwing the ball at the wall constitutes a measurement of its position and so collapses its wave function and thus causes it (the wall) to acquire a definite position, just in time to let the ball bounce off it. But all of this is un-bohmian. In bohm's theory everything is just simple and clear and normal. The wall (meaning, the wall PARTICLE) is, from the beginning, definitely somewhere. Maybe we don't know, for a given run of the experiment, where it is, but who cares. It is somewhere. The ball bounces off this actual wall when it hits this actual wall. Simple.
The question for a Bohmian type theory is what wave function are you using to compute trajectories? The full wave function describes not the actual locations of the particles of the ball and the wall, but a probability amplitude for particles being elsewhere. If, as you seem to agree, the wave function affects the particles, but not the other way around, then the fact that you've gathered atoms into a wall doesn't imply that the wave function is any more highly peaked at the location of the wall.
Well, it certainly implies that there's some kind of "peak" (at the point in configuration space corresponding to the arrangement of atoms you just made). But you're right -- this is just one peak in a vast mountain range, so to speak. There are lots of other peaks. But these, as it turns out, are totally irrelevant. They don't affect the motion of the particles (because, so to speak, the evolution of the actual configuration -- the actual particle positions -- only depends on the structure of the wave function around this actual configuration point... the theory is "local in configuration space"). Of course, there can be interference effects, and so on, but the theory again perfectly agrees with the usual QM predictions -- it just does so without extra ad hoc philosophical magic postulates about what happens during "measurements".
So if it's the wave function that affects the trajectory of the ball, then why should the ball bounce off the wall?
Because that's what the theory's fundamental laws (the Sch eq and the guidance equation) say will happen.
The principle fact that Bohmians use to show that Bohmian mechanics reproduces the predictions of quantum mechanics is that if particles are initially randomly distributed according to the square of the wave function, then the evolution of the wave function and the motion of the particles will maintain this relationship. That's good to know in an ensemble sense, but when you get down to a small number of particles--say one electron--the wave function may say that the electron has equal probabilities of being in New York and in Los Angeles, but the electron is actually only in one of those spots. So either the wave function has to be affected by the actual location (in a mechanism that hasn't been demonstrated, I don't think) or there has to be the possibility of an electron having a location that is in no way related to the wave function (except in the very weak sense that if the electron is at some position, then the wave function has to be nonzero at that position).
I'm not seeing what you think the problem is. Let a single particle come up to a 50/50 beam splitter, and "split in half". Half of the wf goes to LA and half to NY. Ordinary QM says now if you make a measurement of the position (in LA, say) and (say) you actually *find* that the particle is there, that is because some magic happened -- the intervention by the measurement device pre-empted the normal (schroedinger) evolution of the particle's wave function, and made it collapse so that now *all* of its support is in LA, with the "lump" over in NY vanishing. According to Bohm's theory it's much simpler. Particle position detectors don't do anything magical -- they just respond to where the particles is (just like the ball above responds to the actual location of the wall). And note, the word "particle" there means "particle" -- as opposed to the wf! Got that? Particle detectors detect *particles*, not wave function. So the particle detector clicks or beeps or whatever if (as might have been the case with 50% probability) the particle was in fact already actually there in LA. Simple.
So either you have to have a "wave function collapse" or some other way for the wave function to change that doesn't involve evolution according to the Schrodinger equation, or you have the possibility that the trajectories of physical objects are unaffected by the locations of other physical objects. Which is certainly contrary to experience.
You are missing some important points about how the theory works. Hopefully the above clarifies. Note that there is certainly no "collapse postulate" in the axioms of bohm's theory -- the wf (of the universe, basically) obeys the sch eq *all the time*.
HOWEVER, there is a really cool and important thing about bohm's theory -- you can meaningfully define a wave function of a *sub-system*. Take the wall/ball system above. The wave function is a function \psi(x,y). But we also have in the picture the actual wall position X and the actual ball position Y. So we can construct a mathematical object like \psi(x,Y) -- the "universal" wave function, but evaluated at the point y=Y. This is called the "conditional wave function for the wall": \psi_w(x) = \psi(x,Y). And likewise, \psi_b(y) = \psi(X,y) is called the "conditional wave function of the ball".
Now here's the amazingly beautiful thing. Think about how the conditional wave function of the wall, \psi_w(x), evolves in time. To be sure, it starts off having two lumps, one at x=0 and one at x=D. But if you think about how \psi(x,y) evolves in time (with the two lumps becoming *separated* in the y-direction, because one of them reflects earlier than the other), you will see that \psi_w(x) actually "collapses" -- after all the reflecty business has run its course, \psi_w(x) will be *either* a one-lump function peaked at x=0, *or* a one-lump function peaked at x=D. Which one happens depends, of course, on the (random) initial positions of the particles.
The point is -- and this is really truly one of the most important and beautiful things about Bohm's theory -- the theory actually *predicts* (on the basis of fundamental dynamical laws which are simple and clear and which say *nothing* about "collapse" or "measurement") that *sub-system* wave functions (these "conditional wave functions") will collapse, in basically just the kinds of situations where, in ordinary QM, you'd have to bring in your separate measurement axioms to make sure the wfs collapsed appropriately. So not only does bohm's theory make all the right predictions (contrary to what I think you are worrying), it actually manages to *derive* the weird rules about measurement that are instead *postulated* in ordinary QM.