What Does a ≡ b (mod m) Imply in Mathematics?

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The discussion clarifies the mathematical notation a ≡ b (mod m), which indicates that the difference (a - b) is divisible by m. Specifically, for integers a, b, and m (where m > 0), this means that a and b yield the same remainder when divided by m. The example provided illustrates that 10 ≡ 4 (mod 3) holds true because (10 - 4) is divisible by 3. Additionally, the discussion addresses solving the equation (2/3) = x (mod 5), leading to the conclusion that x = 4 is a valid solution when reformulated correctly.

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What exactly does this mean?
a=b (mod m)
My teacher didn't attempt explain this but I'd still like to know.
 
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a \equiv b \mod m, means a is a multiple of m plus b. (a,b and m are integers)

It means when you divide a by b, you get a rest of m.

In algebra, a,b and m are not necessarily integers, but in most cases they are.
 
Last edited:
So how do you solve (2/3)= x (mod 5) for x?
I'm told that x=4, but if m<|b|, then that can't be right.
 
What exactly does this mean?
a=b (mod m)
For integers "a", "b", and "m" (m > 0),
a = b (mod m)
if and only if (a - b) is exactly divisible by "m" (or equivalently, that "a" divided by "m" has the same remainder as "b" divided by "m").

Example:
10 = 4 (mod 3)
---> (10 - 4)/3 = Integer
---> {10 divided by 3} has same remainder as {4 divided by 3}


~~
 
Last edited:
yay_goobers2112 said:
So how do you solve (2/3)= x (mod 5) for x?
I'm told that x=4, but if m<|b|, then that can't be right.
I'm sorry, that remark was wrong. Just use the second one: :biggrin:

a \equiv b \mod m means division of a by b will give rest m.

I'ven't seen fractions on the left side of congruences before, but they probably mean (multiplying both sides by 3):

2 = 3x \mod 5

or

2-3x = 0 \mod 5
So 2-3x must be a multiple of 5, so x =4 will work.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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